Pips answers for Monday, September 21, 2026

Start with the “=” region at the bottom-left: all 3 cells must show the same number, and only 1 or 5 appear on enough dominoes to fill it.

• the “=” region at the top: 1, 1
• the single-cell 1 region at the left: 1
• the “=” region at the bottom-left: 5, 5, 5
• the “=” region at the bottom-right: 1, 1
• the single-cell “>5” region at the right: 6

1. The “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 1–6 domino horizontally on row 2, column 5 and row 2, column 6.
2. The “=” region at the bottom-left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 3, column 2 and row 3, column 3.
3. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top needs every pip to match — nothing else fits. Place the 1–1 domino horizontally on row 1, column 3 and row 1, column 4.
4. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell 1 region at the left needs a total of exactly 1 — nothing else fits. Place the 1–5 domino horizontally on row 2, column 1 and row 2, column 2.
5. Row 3, column 5 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the bottom-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino horizontally on row 3, column 4 and row 3, column 5.

Start with the 6 region at the top: only 0 + 6, or 1 + 5, or 2 + 4 can make it with these dominoes.

• the “=” region at the top-left: 0, 0
• the single-cell “>4” region at the top: 6
• the 6 region at the top: 2, 4
• the “=” region at the center: 1, 1
• the single-cell “>3” region at the right: 4
• the “=” region at the right: 2, 2
• the single-cell “>3” region at the center: 4
• the “>7” region at the bottom-right: 5, 5

1. The 6 region at the top needs a total of exactly 6 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 1, column 3 and row 1, column 4.
2. The “>7” region at the bottom-right must total more than 7 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino vertically on row 3, column 5 and row 4, column 5.
3. The single-cell “>3” region at the right must total more than 3 — nothing else fits. Place the 4–4 domino horizontally on row 2, column 4 and row 2, column 5.
4. The “=” region at the center needs every pip to match — nothing else fits. Place the 1–4 domino horizontally on row 3, column 3 and row 3, column 4.
5. The “=” region at the top-left needs every pip to match — nothing else fits. Place the 0–1 domino horizontally on row 2, column 2 and row 2, column 3.
6. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–0 domino horizontally on row 1, column 1 and row 1, column 2.
7. Row 2, column 6 has only one open neighbor, so its domino must run to row 3, column 6; the “=” region at the right needs every pip to match — nothing else fits. Place the 2–2 domino vertically on row 2, column 6 and row 3, column 6.

Start with the 12 region at the right: the only way to make it with these dominoes is 6 + 6.

• the single-cell 6 region at the top-left: 6
• the single-cell 1 region at the top-left: 1
• the “=” region at the center: 5, 5, 5
• the single-cell 4 region at the top: 4
• the single-cell 0 region at the top: 0
• the single-cell 0 region at the top-right: 0
• the 6 region at the top-right: 1, 5
• the 10 region at the left: 5, 5
• the 9 region at the left: 3, 3, 3
• the “=” region at the center: 0, 0
• the single-cell 6 region at the right: 6
• the 12 region at the right: 6, 6
• the single-cell “<3” region at the left: 2
• the single-cell 1 region at the right: 1
• the “=” region at the bottom: 6, 6, 6
• the “=” region at the bottom-right: 4, 4, 4

1. The 10 region at the left needs a total of exactly 10 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino vertically on row 1, column 1 and row 2, column 1.
2. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 10 region at the left needs a total of exactly 10 (1 of its 2 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino horizontally on row 3, column 1 and row 3, column 2.
3. The single-cell 4 region at the top needs a total of exactly 4 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino horizontally on row 1, column 5 and row 1, column 6.
4. The single-cell 0 region at the top-right needs a total of exactly 0 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–5 domino horizontally on row 1, column 7 and row 1, column 8.
5. Row 1, column 9 has only one open neighbor, so its domino must run to row 2, column 9; the 6 region at the top-right needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino vertically on row 1, column 9 and row 2, column 9.
6. The “=” region at the bottom-right needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino horizontally on row 4, column 7 and row 4, column 8.
7. Row 3, column 9 has only one open neighbor, so its domino must run to row 4, column 9; the 12 region at the right needs a total of exactly 12 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino vertically on row 3, column 9 and row 4, column 9.
8. The single-cell 1 region at the right needs a total of exactly 1 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–1 domino horizontally on row 3, column 6 and row 3, column 7.
9. Row 2, column 6 has only one open neighbor, so its domino must run to row 2, column 7; the “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 2, column 6 and row 2, column 7.
10. The single-cell 1 region at the top-left needs a total of exactly 1 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–5 domino horizontally on row 1, column 3 and row 1, column 4.
11. The “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino vertically on row 2, column 4 and row 3, column 4.
12. The “=” region at the bottom needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino horizontally on row 4, column 5 and row 4, column 6.
13. The 9 region at the left needs a total of exactly 9 — nothing else fits. Place the 3–6 domino horizontally on row 4, column 3 and row 4, column 4.
14. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the 9 region at the left needs a total of exactly 9 (1 of its 3 cells is already filled) — nothing else fits. Place the 3–3 domino vertically on row 2, column 3 and row 3, column 3.