Pips answers for Wednesday, September 30, 2026

Start with the “=” region at the bottom-left: all 3 cells must show the same number, and only 6s appear on enough dominoes to fill it.

• the single-cell 1 region at the top-right: 1
• the “=” region at the bottom-left: 6, 6, 6
• the 1 region at the center: 0, 1
• the 10 region at the bottom-right: 5, 5

1. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 6–6 domino horizontally on row 3, column 1 and row 3, column 2.
2. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the bottom-left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–6 domino horizontally on row 2, column 2 and row 2, column 3.
3. The single-cell 1 region at the top-right needs a total of exactly 1 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–3 domino horizontally on row 1, column 4 and row 1, column 5.
4. The 10 region at the bottom-right needs a total of exactly 10 — nothing else fits. Place the 1–5 domino horizontally on row 2, column 4 and row 2, column 5.
5. Row 3, column 5 has only one open neighbor, so its domino must run to row 3, column 4; the 10 region at the bottom-right needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino horizontally on row 3, column 4 and row 3, column 5.

Start with the “=” region at the bottom: all 3 cells must show the same number, and only 2s appear on enough dominoes to fill it.

• the 11 region at the left: 3, 3, 5
• the single-cell “<2” region at the top-left: 1
• the “≠” region at the top: 4, 5, 6
• the “<8” region at the top-right: 1, 2, 4
• the single-cell 2 region at the left: 2
• the “=” region at the bottom: 2, 2, 2

1. The “=” region at the bottom needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 4, column 2 and row 4, column 3.
2. The “=” region at the bottom needs every pip to match (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 2, column 3 and row 3, column 3.
3. The single-cell 2 region at the left needs a total of exactly 2 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 3, column 1 and row 3, column 2.
4. The 11 region at the left needs a total of exactly 11 (1 of its 3 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 2, column 2 has only one open neighbor, so its domino must run to row 1, column 2; the “≠” region at the top needs every pip to be different (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 1, column 2 and row 2, column 2.
6. The “<8” region at the top-right must total less than 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 2, column 4 and row 2, column 5.
7. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “≠” region at the top needs every pip to be different (2 of its 3 cells are already filled) — nothing else fits. Place the 4–6 domino horizontally on row 1, column 3 and row 1, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 22 region at the top-right: only 4 + 6 + 6 + 6, or 5 + 5 + 6 + 6 can make it with these dominoes.

• the “=” region at the top-left: 4, 4, 4
• the 6 region at the top-left: 2, 4
• the 3 region at the top-right: 0, 0, 3
• the 2 region at the top: 1, 1
• the 22 region at the top-right: 4, 6, 6, 6
• the 9 region at the left: 4, 5
• the 9 region at the bottom-left: 4, 5
• the single-cell “<1” region at the left: 0
• the single-cell “>4” region at the right: 5
• the “=” region at the bottom-right: 2, 2, 2, 2
• the single-cell “>4” region at the bottom: 5
• the “≠” region at the bottom: 1, 3
• the single-cell 2 region at the bottom-right: 2

1. The single-cell “<1” region at the left must total less than 1 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 4, column 1 and row 4, column 2.
2. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the 9 region at the bottom-left needs a total of exactly 9 (1 of its 2 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 5, column 1 and row 6, column 1.
3. The 3 region at the top-right needs a total of exactly 3 — 7 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino horizontally on row 1, column 5 and row 1, column 6.
4. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 3; the 3 region at the top-right needs a total of exactly 3 (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 1, column 3 and row 1, column 4.
5. The “=” region at the bottom-right needs every pip to match — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 5, column 6 and row 6, column 6.
6. The “=” region at the bottom-right needs every pip to match (2 of its 4 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 5, column 4 and row 5, column 5.
7. The “=” region at the bottom-right needs every pip to match (3 of its 4 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 3, column 6 and row 4, column 6.
8. The “≠” region at the bottom needs every pip to be different — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 6, column 4 and row 6, column 5.
9. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 1, column 1 and row 1, column 2.
10. The 2 region at the top needs a total of exactly 2 — nothing else fits. Place the 1–4 domino horizontally on row 2, column 2 and row 2, column 3.
11. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 2, column 1 and row 3, column 1.
12. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the 9 region at the left needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino horizontally on row 3, column 2 and row 3, column 3.
13. The 22 region at the top-right needs a total of exactly 22 (1 of its 4 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 3, column 5 and row 4, column 5.
14. Row 2, column 5 has only one open neighbor, so its domino must run to row 2, column 6; the 22 region at the top-right needs a total of exactly 22 (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 2, column 5 and row 2, column 6.
15. Row 6, column 3 has only one open neighbor, so its domino must run to row 6, column 2; the “≠” region at the bottom needs every pip to be different (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino horizontally on row 6, column 2 and row 6, column 3.

This board has more than one valid layout; the steps follow the official answer.