Pips answers for Sunday, October 4, 2026

Start with the “=” region at the top-left: all 2 cells must show the same number, and only 2 or 5 appear on enough dominoes to fill it.

• the “=” region at the top-left: 2, 2
• the 9 region at the top-right: 4, 5
• the 7 region at the bottom-left: 2, 5
• the 9 region at the bottom-right: 3, 6

1. The 9 region at the top-right needs a total of exactly 9 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 2, column 3 and row 3, column 3.
2. The “=” region at the top-left needs every pip to match — nothing else fits. Place the 2–4 domino horizontally on row 1, column 2 and row 1, column 3.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 7 region at the bottom-left needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino horizontally on row 3, column 1 and row 3, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the center: all 4 cells must show the same number, and only 5s appear on enough dominoes to fill it.

• the single-cell “<3” region at the top-right: 2
• the “≠” region at the top: 3, 4, 5
• the single-cell “>3” region at the left: 6
• the “=” region at the center: 5, 5, 5, 5
• the single-cell 1 region at the bottom-left: 1
• the single-cell 2 region at the bottom: 2
• the single-cell 1 region at the bottom-right: 1

1. The single-cell 2 region at the bottom needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 4, column 3 and row 5, column 3.
2. The “=” region at the center needs every pip to match — nothing else fits. Place the 5–5 domino horizontally on row 3, column 3 and row 3, column 4.
3. The “=” region at the center needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 1–5 domino horizontally on row 4, column 1 and row 4, column 2.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “>3” region at the left must total more than 3 — nothing else fits. Place the 5–6 domino horizontally on row 3, column 1 and row 3, column 2.
5. Row 5, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the single-cell 1 region at the bottom-right needs a total of exactly 1 — nothing else fits. Place the 1–3 domino vertically on row 4, column 4 and row 5, column 4.
6. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the single-cell “<3” region at the top-right must total less than 3 — nothing else fits. Place the 2–4 domino vertically on row 1, column 4 and row 2, column 4.
7. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the “≠” region at the top needs every pip to be different (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 2, column 2 and row 2, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the 3 region at the top-left: only 0 + 3, or 1 + 2 can make it with these dominoes.

• the 3 region at the top-left: 0, 3
• the 8 region at the top: 3, 5
• the single-cell “<2” region at the top: 1
• the 3 region at the top-right: 0, 3
• the “=” region at the left: 4, 4, 4
• the single-cell 2 region at the top-left: 2
• the “≠” region at the top-right: 4, 5
• the single-cell 2 region at the top-right: 2
• the “=” region at the right: 2, 2, 2
• the single-cell “<2” region at the center: 1
• the single-cell “>5” region at the bottom-left: 6
• the “≠” region at the bottom: 1, 5
• the single-cell 0 region at the bottom-right: 0
• the 3 region at the bottom-left: 0, 3
• the single-cell 3 region at the bottom: 3

1. Row 6, column 1 has only one open neighbor, so its domino must run to row 6, column 2; the 3 region at the bottom-left needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 6, column 1 and row 6, column 2.
2. The single-cell “>5” region at the bottom-left must total more than 5 — nothing else fits. Place the 3–6 domino vertically on row 4, column 2 and row 5, column 2.
3. The “=” region at the left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 3, column 1 and row 4, column 1.
4. The “=” region at the right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 3, column 6 and row 4, column 6.
5. The 3 region at the top-left needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 1, column 1 and row 2, column 1.
6. The 3 region at the top-right needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 1, column 6 and row 2, column 6.
7. The “≠” region at the bottom needs every pip to be different — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 5, column 3 and row 6, column 3.
8. The single-cell 2 region at the top-left needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 1, column 2 and row 2, column 2.
9. The “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 2–4 domino vertically on row 5, column 6 and row 6, column 6.
10. The single-cell 0 region at the bottom-right needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 5, column 5 and row 6, column 5.
11. The 3 region at the top-right needs a total of exactly 3 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 1, column 4 and row 1, column 5.
12. Row 4, column 4 has only one open neighbor, so its domino must run to row 5, column 4; the single-cell “<2” region at the center must total less than 2 — nothing else fits. Place the 1–5 domino vertically on row 4, column 4 and row 5, column 4.
13. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the 8 region at the top needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 1, column 3 and row 2, column 3.
14. Row 2, column 4 has only one open neighbor, so its domino must run to row 2, column 5; the “≠” region at the top-right needs every pip to be different — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 2, column 4 and row 2, column 5.

This board has more than one valid layout; the steps follow the official answer.