Pips answers for Sunday, October 11, 2026

Start with the 7 region at the bottom-left: the only way to make it with these dominoes is 3 + 4.

• the “=” region at the top-right: 2, 2, 2
• the 7 region at the bottom-left: 3, 4
• the “=” region at the center: 4, 4, 4
• the single-cell “>4” region at the right: 6
• the single-cell “<2” region at the bottom-left: 0

1. The “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 1, column 4 and row 1, column 5.
2. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the top-right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 2–4 domino vertically on row 1, column 3 and row 2, column 3.
3. Row 2, column 4 has only one open neighbor, so its domino must run to row 2, column 5; the “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 4–6 domino horizontally on row 2, column 4 and row 2, column 5.
4. The “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 2, column 1 and row 2, column 2.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 7 region at the bottom-left needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino horizontally on row 3, column 1 and row 3, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the 6 region at the top-right: only 1 + 5, or 2 + 4 can make it with these dominoes.

• the single-cell “<2” region at the top-left: 1
• the “=” region at the top: 2, 2
• the 6 region at the top-right: 2, 4
• the 4 region at the left: 0, 4
• the 2 region at the right: 0, 2
• the single-cell “<2” region at the bottom: 0
• the “>7” region at the bottom-right: 5, 5

1. The “>7” region at the bottom-right must total more than 7 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino horizontally on row 4, column 2 and row 4, column 3.
2. Row 4, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “>7” region at the bottom-right must total more than 7 (1 of its 2 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino vertically on row 3, column 4 and row 4, column 4.
3. The single-cell “<2” region at the top-left must total less than 2 — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the 4 region at the left needs a total of exactly 4 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 3, column 1 and row 4, column 1.
5. The “=” region at the top needs every pip to match — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino horizontally on row 2, column 2 and row 2, column 3.
6. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 1, column 2 and row 1, column 3.
7. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the 6 region at the top-right needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 1, column 4 and row 2, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 2 region at the top-right: only 0 + 2, or 1 + 1 can make it with these dominoes.

• the single-cell 5 region at the top-left: 5
• the single-cell “>1” region at the top: 6
• the single-cell 3 region at the top-right: 3
• the single-cell 4 region at the top-right: 4
• the 6 region at the top-left: 2, 4
• the single-cell “>4” region at the top-left: 5
• the 2 region at the top-right: 0, 2
• the single-cell “>4” region at the left: 5
• the 10 region at the center: 4, 6
• the single-cell “<5” region at the left: 4
• the “=” region at the bottom: 0, 0, 0
• the single-cell 4 region at the right: 4
• the single-cell 3 region at the right: 3
• the 5 region at the bottom-left: 2, 3
• the 8 region at the bottom-right: 2, 6
• the “=” region at the bottom-right: 2, 2

1. The single-cell “>4” region at the top-left must total more than 4 — nothing else fits. Place the 5–5 domino vertically on row 2, column 2 and row 3, column 2.
2. The 6 region at the top-left needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 1, column 1 and row 2, column 1.
3. The 5 region at the bottom-left needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 5, column 1 and row 6, column 1.
4. The single-cell 3 region at the top-right needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 1, column 6 and row 2, column 6.
5. The single-cell 3 region at the right needs a total of exactly 3 — nothing else fits. Place the 3–6 domino vertically on row 4, column 7 and row 5, column 7.
6. The 8 region at the bottom-right needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino vertically on row 4, column 6 and row 5, column 6.
7. Row 1, column 7 has only one open neighbor, so its domino must run to row 2, column 7; the single-cell 4 region at the top-right needs a total of exactly 4 — nothing else fits. Place the 0–4 domino vertically on row 1, column 7 and row 2, column 7.
8. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the 6 region at the top-left needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 3, column 1 and row 4, column 1.
9. The “=” region at the bottom needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 5, column 4 and row 6, column 4.
10. The 10 region at the center needs a total of exactly 10 — nothing else fits. Place the 0–6 domino horizontally on row 4, column 3 and row 4, column 4.
11. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the 10 region at the center needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino horizontally on row 3, column 3 and row 3, column 4.
12. Row 6, column 6 has only one open neighbor, so its domino must run to row 6, column 7; the “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 2–2 domino horizontally on row 6, column 6 and row 6, column 7.
13. Row 3, column 7 has only one open neighbor, so its domino must run to row 3, column 6; the 2 region at the top-right needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino horizontally on row 3, column 6 and row 3, column 7.
14. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the single-cell “>1” region at the top must total more than 1 — nothing else fits. Place the 1–6 domino vertically on row 1, column 4 and row 2, column 4.

This board has more than one valid layout; the steps follow the official answer.