Pips answers for Wednesday, October 21, 2026

Start with the 10 region at the top-left: the only way to make it with these dominoes is 4 + 6.

• the 10 region at the top-left: 4, 6
• the 10 region at the top-right: 4, 6
• the single-cell “>4” region at the top-right: 6
• the 5 region at the center: 2, 3
• the single-cell “<1” region at the bottom: 0

1. The 10 region at the top-right needs a total of exactly 10 — nothing else fits. Place the 6–6 domino horizontally on row 1, column 5 and row 1, column 6.
2. The 5 region at the center needs a total of exactly 5 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–4 domino horizontally on row 2, column 4 and row 2, column 5.
3. The 10 region at the top-left needs a total of exactly 10 — nothing else fits. Place the 3–6 domino horizontally on row 2, column 2 and row 2, column 3.
4. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the 10 region at the top-left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino horizontally on row 1, column 1 and row 1, column 2.
5. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 3; the single-cell “<1” region at the bottom must total less than 1 — nothing else fits. Place the 0–1 domino horizontally on row 3, column 3 and row 3, column 4.

Start with the 8 region at the bottom: only 2 + 6, or 3 + 5, or 4 + 4 can make it with these dominoes.

• the single-cell “>4” region at the top-left: 5
• the “≠” region at the top: 0, 1, 2
• the “=” region at the top-right: 1, 1
• the “>7” region at the left: 3, 5
• the “>5” region at the center: 2, 4
• the single-cell 6 region at the right: 6
• the 8 region at the bottom: 4, 4

1. The “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 1, column 4 and row 1, column 5.
2. The single-cell 6 region at the right needs a total of exactly 6 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 3, column 3 and row 3, column 4.
3. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the 8 region at the bottom needs a total of exactly 8 — nothing else fits. Place the 4–4 domino horizontally on row 4, column 3 and row 4, column 4.
4. The “≠” region at the top needs every pip to be different — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 1, column 2 and row 1, column 3.
5. The “>7” region at the left must total more than 7 — nothing else fits. Place the 3–4 domino horizontally on row 3, column 1 and row 3, column 2.
6. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the “>7” region at the left must total more than 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino horizontally on row 2, column 1 and row 2, column 2.
7. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 4; the “≠” region at the top needs every pip to be different (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 2, column 3 and row 2, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 0 region at the bottom: the only way to make it with these dominoes is 0 + 0.

• the single-cell “<3” region at the top-left: 2
• the single-cell “>3” region at the top: 4
• the “=” region at the top: 4, 4, 4
• the single-cell 5 region at the top-right: 5
• the single-cell “>1” region at the top-right: 2
• the single-cell 2 region at the top-left: 2
• the “<3” region at the top-left: 0, 2
• the single-cell 1 region at the top: 1
• the single-cell 5 region at the top-right: 5
• the “=” region at the left: 5, 5
• the single-cell “>0” region at the center: 4
• the single-cell 5 region at the center: 5
• the single-cell 3 region at the right: 3
• the 9 region at the left: 3, 6
• the 7 region at the center: 1, 2, 4
• the single-cell 3 region at the right: 3
• the “≠” region at the bottom-right: 1, 4
• the 3 region at the bottom-left: 1, 2
• the 0 region at the bottom: 0, 0
• the single-cell 3 region at the bottom: 3
• the single-cell 5 region at the bottom-right: 5

1. The 0 region at the bottom needs a total of exactly 0 — nothing else fits. Place the 0–0 domino vertically on row 5, column 4 and row 6, column 4.
2. The “<3” region at the top-left must total less than 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 2, column 2 and row 3, column 2.
3. The 3 region at the bottom-left needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 5, column 1 and row 6, column 1.
4. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell “<3” region at the top-left must total less than 3 — nothing else fits. Place the 2–2 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “=” region at the left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino vertically on row 3, column 1 and row 4, column 1.
6. The “=” region at the top needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino horizontally on row 1, column 6 and row 1, column 7.
7. Row 2, column 6 has only one open neighbor, so its domino must run to row 3, column 6; the “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 4–5 domino vertically on row 2, column 6 and row 3, column 6.
8. The single-cell 5 region at the top-right needs a total of exactly 5 — nothing else fits. Place the 3–5 domino vertically on row 2, column 9 and row 3, column 9.
9. Row 1, column 8 has only one open neighbor, so its domino must run to row 1, column 9; the single-cell 5 region at the top-right needs a total of exactly 5 — nothing else fits. Place the 2–5 domino horizontally on row 1, column 8 and row 1, column 9.
10. The “≠” region at the bottom-right needs every pip to be different — nothing else fits. Place the 1–5 domino vertically on row 5, column 9 and row 6, column 9.
11. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the single-cell “>3” region at the top must total more than 3 — nothing else fits. Place the 1–4 domino vertically on row 1, column 4 and row 2, column 4.
12. Row 4, column 9 has only one open neighbor, so its domino must run to row 4, column 8; the “≠” region at the bottom-right needs every pip to be different (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 4, column 8 and row 4, column 9.
13. The 7 region at the center needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 5, column 6 and row 6, column 6.
14. Row 4, column 6 has only one open neighbor, so its domino must run to row 4, column 7; the 7 region at the center needs a total of exactly 7 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 4, column 6 and row 4, column 7.
15. The 9 region at the left needs a total of exactly 9 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 4, column 3 and row 4, column 4.
16. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 3; the single-cell “>0” region at the center must total more than 0 — nothing else fits. Place the 0–4 domino horizontally on row 3, column 3 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.