Pips answers for Tuesday, October 27, 2026

Start with the “=” region at the center: all 2 cells must show the same number, and only 1 or 2 or 3 appear on enough dominoes to fill it.

• the single-cell “<2” region at the top-left: 0
• the “=” region at the center: 1, 1
• the “=” region at the right: 3, 3
• the single-cell 2 region at the bottom-left: 2
• the single-cell “>2” region at the bottom: 5
• the single-cell 2 region at the bottom-right: 2

1. The “=” region at the right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino vertically on row 2, column 5 and row 3, column 5.
2. The “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 1, column 4 and row 2, column 4.
3. Row 3, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell 2 region at the bottom-left needs a total of exactly 2 — nothing else fits. Place the 2–6 domino vertically on row 2, column 1 and row 3, column 1.
4. The “=” region at the center needs every pip to match — nothing else fits. Place the 1–5 domino vertically on row 2, column 3 and row 3, column 3.
5. Row 1, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell “<2” region at the top-left must total less than 2 — nothing else fits. Place the 0–1 domino vertically on row 1, column 2 and row 2, column 2.

Start with the 7 region at the bottom-right: only 1 + 6, or 3 + 4 can make it with these dominoes.

• the “<4” region at the top: 0, 0, 3
• the “>7” region at the left: 2, 6
• the single-cell “<1” region at the top-right: 0
• the single-cell “<3” region at the right: 2
• the single-cell 4 region at the bottom: 4
• the 7 region at the bottom-right: 1, 6
• the single-cell “>2” region at the bottom: 3

1. The single-cell 4 region at the bottom needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 3, column 2 and row 4, column 2.
2. The “>7” region at the left must total more than 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 2, column 1 and row 3, column 1.
3. The single-cell “<1” region at the top-right must total less than 1 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 2, column 4 and row 3, column 4.
4. Row 1, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the “<4” region at the top must total less than 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 1, column 2 and row 2, column 2.
5. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the “<4” region at the top must total less than 4 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–6 domino vertically on row 2, column 3 and row 3, column 3.
6. The 7 region at the bottom-right needs a total of exactly 7 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 4, column 4 and row 5, column 4.
7. Row 5, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the single-cell “>2” region at the bottom must total more than 2 — nothing else fits. Place the 2–3 domino vertically on row 4, column 3 and row 5, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the top-left: all 4 cells must show the same number, and only 1 or 4 appear on enough dominoes to fill it.

• the single-cell 6 region at the top-left: 6
• the 15 region at the left: 2, 2, 5, 6
• the single-cell “>3” region at the top-left: 4
• the “=” region at the center: 4, 4, 4
• the 7 region at the right: 3, 4
• the “≠” region at the right: 0, 1, 2
• the 4 region at the bottom: 0, 1, 3
• the single-cell “>4” region at the bottom-left: 5
• the single-cell “<4” region at the bottom-left: 3
• the “<2” region at the bottom-right: 0, 1
• the single-cell 5 region at the bottom-left: 5
• the “=” region at the top-left: 1, 1, 1, 1

1. The single-cell “<4” region at the bottom-left must total less than 4 — nothing else fits. Place the 3–5 domino vertically on row 9, column 3 and row 10, column 3.
2. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 1, column 3 and row 2, column 3.
3. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the “=” region at the top-left needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 1–1 domino horizontally on row 2, column 1 and row 2, column 2.
4. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the “=” region at the top-left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 1–4 domino horizontally on row 3, column 2 and row 3, column 3.
5. The 15 region at the left needs a total of exactly 15 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino vertically on row 7, column 3 and row 8, column 3.
6. The “<2” region at the bottom-right must total less than 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 9, column 6 and row 10, column 6.
7. The 4 region at the bottom needs a total of exactly 4 — 8 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 7, column 6 and row 8, column 6.
8. The “=” region at the center needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 7, column 4 and row 7, column 5.
9. The 15 region at the left needs a total of exactly 15 (1 of its 4 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 6, column 3 and row 6, column 4.
10. Row 6, column 5 has only one open neighbor, so its domino must run to row 6, column 6; the “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 4–4 domino horizontally on row 6, column 5 and row 6, column 6.
11. Row 6, column 7 has only one open neighbor, so its domino must run to row 6, column 8; the 7 region at the right needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino horizontally on row 6, column 7 and row 6, column 8.
12. Row 4, column 3 has only one open neighbor, so its domino must run to row 5, column 3; the 15 region at the left needs a total of exactly 15 (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 4, column 3 and row 5, column 3.
13. Row 7, column 8 has only one open neighbor, so its domino must run to row 8, column 8; the “≠” region at the right needs every pip to be different (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 7, column 8 and row 8, column 8.

This board has more than one valid layout; the steps follow the official answer.