Pips answers for Friday, August 22, 2025

Start with the 8 region at the right: the only way to make it with these dominoes is 3 + 5.

• the single-cell 1 region at the top-left: 1
• the single-cell 0 region at the top-right: 0
• the single-cell 1 region at the left: 1
• the 8 region at the right: 3, 5
• the “=” region at the bottom-left: 1, 1

1. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell 0 region at the top-right needs a total of exactly 0 — nothing else fits. Place the 0–6 domino horizontally on row 1, column 2 and row 1, column 3.
2. Row 5, column 1 has only one open neighbor, so its domino must run to row 5, column 2; the “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 1–1 domino horizontally on row 5, column 1 and row 5, column 2.
3. The 8 region at the right needs a total of exactly 8 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–5 domino horizontally on row 3, column 1 and row 3, column 2.
4. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell 1 region at the top-left needs a total of exactly 1 — nothing else fits. Place the 1–6 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the 8 region at the right needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 3, column 3 and row 4, column 3.

Start with the “=” region at the center: all 3 cells must show the same number, and only 5s appear on enough dominoes to fill it.

• the 3 region at the top: 0, 3
• the “=” region at the center: 5, 5, 5
• the single-cell 5 region at the left: 5
• the “=” region at the bottom: 6, 6
• the 6 region at the bottom-right: 1, 1, 4

1. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the 6 region at the bottom-right needs a total of exactly 6 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–1 domino vertically on row 3, column 4 and row 4, column 4.
2. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 2; the 6 region at the bottom-right needs a total of exactly 6 (2 of its 3 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino horizontally on row 4, column 2 and row 4, column 3.
3. The 3 region at the top needs a total of exactly 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–5 domino vertically on row 1, column 3 and row 2, column 3.
4. The 3 region at the top needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino horizontally on row 1, column 1 and row 1, column 2.
5. The “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 2, column 1 and row 2, column 2.
6. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell 5 region at the left needs a total of exactly 5 — nothing else fits. Place the 5–6 domino horizontally on row 3, column 1 and row 3, column 2.

Start with the 0 region at the top: the only way to make it with these dominoes is 0 + 0 + 0 + 0 + 0.

• the 18 region at the top: 6, 6, 6
• the “=” region at the top-right: 2, 2, 2
• the 0 region at the top: 0, 0, 0, 0, 0
• the single-cell 1 region at the left: 1
• the “=” region at the bottom: 4, 4
• the single-cell 2 region at the bottom-right: 2
• the “=” region at the bottom-right: 3, 3

1. The 18 region at the top needs a total of exactly 18 — nothing else fits. Place the 6–6 domino horizontally on row 1, column 2 and row 1, column 3.
2. The 0 region at the top needs a total of exactly 0 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–1 domino vertically on row 3, column 2 and row 4, column 2.
3. The 18 region at the top needs a total of exactly 18 (2 of its 3 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino vertically on row 1, column 4 and row 2, column 4.
4. The 0 region at the top needs a total of exactly 0 (1 of its 5 cells is already filled) — nothing else fits. Place the 0–0 domino vertically on row 2, column 3 and row 3, column 3.
5. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the “=” region at the top-right needs every pip to match — nothing else fits. Place the 2–2 domino vertically on row 1, column 5 and row 2, column 5.
6. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 5; the 0 region at the top needs a total of exactly 0 (3 of its 5 cells are already filled) — nothing else fits. Place the 0–2 domino horizontally on row 3, column 4 and row 3, column 5.
7. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 1; the 0 region at the top needs a total of exactly 0 (4 of its 5 cells are already filled) — nothing else fits. Place the 0–5 domino horizontally on row 2, column 1 and row 2, column 2.
8. Row 5, column 5 has only one open neighbor, so its domino must run to row 6, column 5; the single-cell 2 region at the bottom-right needs a total of exactly 2 — nothing else fits. Place the 2–3 domino vertically on row 5, column 5 and row 6, column 5.
9. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 3–4 domino horizontally on row 6, column 3 and row 6, column 4.
10. Row 5, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino vertically on row 4, column 3 and row 5, column 3.