Pips answers for Saturday, August 23, 2025

Start with the 1 region at the top-right: the only way to make it with these dominoes is 0 + 1.

• the 1 region at the top-right: 0, 1
• the “=” region at the center: 3, 3, 3
• the 4 region at the bottom-left: 0, 4

1. The 1 region at the top-right needs a total of exactly 1 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 1, column 3 and row 2, column 3.
2. The “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 2, column 1 and row 2, column 2.
3. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the 1 region at the top-right needs a total of exactly 1 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino horizontally on row 1, column 1 and row 1, column 2.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 4 region at the bottom-left needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 3, column 1 and row 3, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the 12 region at the left: the only way to make it with these dominoes is 6 + 6.

• the single-cell “<2” region at the top: 1
• the “=” region at the top-right: 5, 5, 5
• the 12 region at the left: 6, 6
• the “=” region at the bottom: 4, 4, 4

1. The “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino horizontally on row 2, column 2 and row 2, column 3.
2. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the single-cell “<2” region at the top must total less than 2 — nothing else fits. Place the 1–5 domino horizontally on row 1, column 2 and row 1, column 3.
3. The “=” region at the bottom needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 4, column 1 and row 4, column 2.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the 12 region at the left needs a total of exactly 12 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino vertically on row 2, column 1 and row 3, column 1.
5. Row 4, column 3 has only one open neighbor, so its domino must run to row 5, column 3; the “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 4, column 3 and row 5, column 3.
6. Row 5, column 2 has only one open neighbor, so its domino must run to row 5, column 1; the “=” region at the bottom needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 3–4 domino horizontally on row 5, column 1 and row 5, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the bottom-left: all 4 cells must show the same number, and only 0 or 1 or 6 appear on enough dominoes to fill it.

• the “<6” region at the right: 0, 1, 1, 1
• the 4 region at the top: 0, 0, 2, 2
• the single-cell 3 region at the top-right: 3
• the “=” region at the bottom-left: 1, 1, 1, 1
• the single-cell 6 region at the center: 6
• the single-cell “>2” region at the bottom: 3
• the single-cell 6 region at the bottom: 6
• the single-cell 6 region at the bottom-left: 6
• the single-cell 6 region at the bottom: 6

1. The single-cell “>2” region at the bottom must total more than 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 4, column 4 and row 4, column 5.
2. The single-cell 3 region at the top-right needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 2, column 7 and row 2, column 8.
3. The 4 region at the top needs a total of exactly 4 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 2, column 5 and row 3, column 5.
4. Row 5, column 4 has only one open neighbor, so its domino must run to row 5, column 5; the single-cell 6 region at the bottom needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino horizontally on row 5, column 4 and row 5, column 5.
5. The single-cell 6 region at the bottom-left needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 4, column 2 and row 5, column 2.
6. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the “=” region at the bottom-left needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 1–1 domino vertically on row 4, column 1 and row 5, column 1.
7. The 4 region at the top needs a total of exactly 4 (1 of its 4 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 2, column 2 and row 3, column 2.
8. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 4; the 4 region at the top needs a total of exactly 4 (2 of its 4 cells are already filled) — nothing else fits. Place the 0–0 domino horizontally on row 2, column 3 and row 2, column 4.
9. Row 3, column 7 has only one open neighbor, so its domino must run to row 4, column 7; the “<6” region at the right must total less than 6 (1 of its 4 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 3, column 7 and row 4, column 7.
10. Row 1, column 7 has only one open neighbor, so its domino must run to row 1, column 8; the “<6” region at the right must total less than 6 (3 of its 4 cells are already filled) — nothing else fits. Place the 1–4 domino horizontally on row 1, column 7 and row 1, column 8.

This board has more than one valid layout; the steps follow the official answer.