Pips answers for Tuesday, November 18, 2025

Start with the “=” region at the right: all 3 cells must show the same number, and only 0s appear on enough dominoes to fill it.

• the “=” region at the top-left: 6, 6
• the “=” region at the right: 0, 0, 0
• the 8 region at the bottom-left: 4, 4

1. The “=” region at the right needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 2, column 3 and row 3, column 3.
2. The “=” region at the top-left needs every pip to match — nothing else fits. Place the 0–6 domino horizontally on row 1, column 2 and row 1, column 3.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 8 region at the bottom-left needs a total of exactly 8 — nothing else fits. Place the 4–4 domino horizontally on row 3, column 1 and row 3, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the “=” region at the left: all 4 cells must show the same number, and only 2s appear on enough dominoes to fill it.

• the 5 region at the top-left: 1, 4
• the single-cell 1 region at the top-right: 1
• the “=” region at the left: 2, 2, 2, 2
• the “=” region at the right: 0, 0
• the “=” region at the bottom: 3, 3
• the 11 region at the bottom-left: 5, 6
• the single-cell 4 region at the bottom-right: 4

1. The “=” region at the right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 1, column 5 and row 2, column 5.
2. The “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino horizontally on row 2, column 3 and row 2, column 4.
3. The 11 region at the bottom-left needs a total of exactly 11 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 3, column 1 and row 4, column 1.
4. The 11 region at the bottom-left needs a total of exactly 11 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 3, column 2 and row 4, column 2.
5. The “=” region at the left needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 2, column 1 and row 2, column 2.
6. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 5 region at the top-left needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 1, column 1 and row 1, column 2.
7. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 3–4 domino horizontally on row 4, column 3 and row 4, column 4.
8. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino horizontally on row 3, column 3 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 9 region at the right: the only way to make it with these dominoes is 1 + 2 + 2 + 2 + 2.

• the 9 region at the top-left: 3, 6
• the single-cell 3 region at the top: 3
• the 9 region at the top-right: 2, 2, 5
• the 9 region at the left: 4, 5
• the 9 region at the right: 1, 2, 2, 2, 2
• the 9 region at the bottom-right: 3, 6
• the “=” region at the bottom-left: 5, 5

1. The 9 region at the top-left needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 1, column 1 and row 1, column 2.
2. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the 9 region at the top-left needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino vertically on row 2, column 1 and row 3, column 1.
3. The 9 region at the right needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 4, column 1 and row 4, column 2.
4. Row 7, column 1 has only one open neighbor, so its domino must run to row 7, column 2; the “=” region at the bottom-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino horizontally on row 7, column 1 and row 7, column 2.
5. The 9 region at the right needs a total of exactly 9 (1 of its 5 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 5, column 4 and row 6, column 4.
6. Row 7, column 4 has only one open neighbor, so its domino must run to row 7, column 3; the 9 region at the bottom-right needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino horizontally on row 7, column 3 and row 7, column 4.
7. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the 9 region at the right needs a total of exactly 9 (2 of its 5 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 4, column 3 and row 4, column 4.
8. The 9 region at the top-right needs a total of exactly 9 — nothing else fits. Place the 1–2 domino vertically on row 2, column 4 and row 3, column 4.
9. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the 9 region at the top-right needs a total of exactly 9 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 1, column 3 and row 1, column 4.

This board has more than one valid layout; the steps follow the official answer.