Pips answers for Wednesday, November 19, 2025

Start with the “=” region at the center: all 3 cells must show the same number, and only 3s appear on enough dominoes to fill it.

• the single-cell 4 region at the top-right: 4
• the single-cell 4 region at the left: 4
• the “=” region at the center: 3, 3, 3
• the “<3” region at the right: 1, 1

1. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell 4 region at the top-right needs a total of exactly 4 — nothing else fits. Place the 1–4 domino vertically on row 1, column 3 and row 2, column 3.
2. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell 4 region at the left needs a total of exactly 4 — nothing else fits. Place the 3–4 domino horizontally on row 2, column 1 and row 2, column 2.
3. The “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 1–3 domino horizontally on row 3, column 2 and row 3, column 3.
4. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 3–5 domino horizontally on row 4, column 2 and row 4, column 3.

Start with the 7 region at the top-right — it has the fewest pip combinations on the board, so the dominoes around it are the easiest to pin down.

• the single-cell “>3” region at the top-left: 4
• the 7 region at the top-right: 1, 3, 3
• the single-cell “>2” region at the left: 3
• the single-cell “>4” region at the left: 6
• the single-cell “>4” region at the center: 5
• the single-cell “>4” region at the right: 5
• the single-cell “>1” region at the bottom: 2
• the single-cell “>2” region at the bottom-right: 4

1. The single-cell “>4” region at the right must total more than 4 — nothing else fits. Place the 4–5 domino vertically on row 3, column 5 and row 4, column 5.
2. The single-cell “>4” region at the center must total more than 4 — nothing else fits. Place the 2–5 domino vertically on row 3, column 3 and row 4, column 3.
3. The single-cell “>4” region at the left must total more than 4 — nothing else fits. Place the 1–6 domino vertically on row 3, column 1 and row 4, column 1.
4. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell “>3” region at the top-left must total more than 3 — nothing else fits. Place the 0–4 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “>2” region at the left must total more than 2 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino vertically on row 2, column 2 and row 3, column 2.
6. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the 7 region at the top-right needs a total of exactly 7 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 1, column 5 and row 2, column 5.
7. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the 7 region at the top-right needs a total of exactly 7 (2 of its 3 cells are already filled) — nothing else fits. Place the 1–1 domino vertically on row 2, column 4 and row 3, column 4.

Start with the “=” region at the left: all 6 cells must show the same number, and only 0s appear on enough dominoes to fill it.

• the “=” region at the left: 0, 0, 0, 0, 0, 0
• the 10 region at the top-left: 2, 3, 5
• the 10 region at the top-right: 2, 2, 3, 3
• the “=” region at the top-right: 1, 1
• the 10 region at the center: 5, 5
• the 10 region at the right: 4, 6
• the 10 region at the bottom-left: 4, 6
• the 10 region at the bottom: 5, 5
• the 10 region at the bottom-right: 4, 6

1. The 10 region at the center needs a total of exactly 10 — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino vertically on row 4, column 5 and row 5, column 5.
2. Row 5, column 6 has only one open neighbor, so its domino must run to row 5, column 7; the 10 region at the bottom needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino horizontally on row 5, column 6 and row 5, column 7.
3. The 10 region at the right needs a total of exactly 10 — nothing else fits. Place the 6–6 domino vertically on row 4, column 8 and row 5, column 8.
4. The 10 region at the top-right needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 2, column 5 and row 3, column 5.
5. The “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 2, column 8 and row 3, column 8.
6. The 10 region at the top-right needs a total of exactly 10 (1 of its 4 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 1, column 7 and row 1, column 8.
7. Row 1, column 5 has only one open neighbor, so its domino must run to row 1, column 6; the 10 region at the top-right needs a total of exactly 10 (2 of its 4 cells are already filled) — nothing else fits. Place the 2–2 domino horizontally on row 1, column 5 and row 1, column 6.
8. The 10 region at the bottom-left needs a total of exactly 10 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino horizontally on row 5, column 2 and row 5, column 3.
9. The “=” region at the left needs every pip to match (1 of its 6 cells is already filled) — nothing else fits. Place the 0–0 domino vertically on row 3, column 2 and row 4, column 2.
10. The 10 region at the top-left needs a total of exactly 10 — nothing else fits. Place the 3–4 domino vertically on row 3, column 3 and row 4, column 3.
11. The “=” region at the left needs every pip to match (3 of its 6 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino horizontally on row 1, column 2 and row 1, column 3.
12. The “=” region at the left needs every pip to match (4 of its 6 cells are already filled) — nothing else fits. Place the 0–5 domino horizontally on row 2, column 2 and row 2, column 3.
13. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the left needs every pip to match (5 of its 6 cells are already filled) — nothing else fits. Place the 0–1 domino vertically on row 2, column 1 and row 3, column 1.

This board has more than one valid layout; the steps follow the official answer.