Pips answers for Sunday, December 28, 2025

Start with the “=” region at the right: all 3 cells must show the same number, and only 3s appear on enough dominoes to fill it.

• the single-cell 5 region at the top: 5
• the “=” region at the top-right: 6, 6
• the “=” region at the right: 3, 3, 3
• the single-cell 5 region at the bottom-left: 5
• the “=” region at the bottom-left: 2, 2
• the single-cell 4 region at the bottom-right: 4

1. The “=” region at the top-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino horizontally on row 1, column 2 and row 1, column 3.
2. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino vertically on row 2, column 3 and row 3, column 3.
3. The “=” region at the right needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 4, column 3 and row 5, column 3.
4. The “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–5 domino horizontally on row 4, column 1 and row 4, column 2.
5. Row 5, column 1 has only one open neighbor, so its domino must run to row 5, column 2; the “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 2–2 domino horizontally on row 5, column 1 and row 5, column 2.

Start with the 6 region at the bottom: only 0 + 6, or 3 + 3 can make it with these dominoes.

• the single-cell “>3” region at the top: 6
• the “≠” region at the center: 0, 1, 2, 3
• the 8 region at the right: 2, 2, 2, 2
• the single-cell 0 region at the left: 0
• the 6 region at the bottom: 3, 3

1. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell “>3” region at the top must total more than 3 — nothing else fits. Place the 2–6 domino vertically on row 1, column 3 and row 2, column 3.
2. The single-cell 0 region at the left needs a total of exactly 0 — 5 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino horizontally on row 3, column 1 and row 3, column 2.
3. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 1; the “≠” region at the center needs every pip to be different (2 of its 4 cells are already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–1 domino horizontally on row 2, column 1 and row 2, column 2.
4. The “≠” region at the center needs every pip to be different (3 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino horizontally on row 3, column 3 and row 3, column 4.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 2, column 5; the 8 region at the right needs a total of exactly 8 (1 of its 4 cells is already filled) — 5 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino horizontally on row 2, column 4 and row 2, column 5.
6. The 6 region at the bottom needs a total of exactly 6 — nothing else fits. Place the 2–3 domino horizontally on row 4, column 3 and row 4, column 4.
7. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 1; the 6 region at the bottom needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino horizontally on row 4, column 1 and row 4, column 2.

Start with the 15 region at the top-left: only 4 + 5 + 6, or 5 + 5 + 5 can make it with these dominoes.

• the 15 region at the top-left: 4, 5, 6
• the single-cell “>4” region at the top: 5
• the “=” region at the top-right: 1, 1, 1
• the 15 region at the top-left: 4, 5, 6
• the “=” region at the left: 0, 0, 0
• the 15 region at the center: 4, 5, 6
• the single-cell “>3” region at the bottom-right: 4
• the “=” region at the bottom-left: 2, 2, 2, 2

1. The “=” region at the bottom-left needs every pip to match — 6 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino horizontally on row 8, column 1 and row 8, column 2.
2. The “=” region at the bottom-left needs every pip to match (2 of its 4 cells are already filled) — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino vertically on row 6, column 1 and row 7, column 1.
3. The “=” region at the left needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–5 domino horizontally on row 5, column 1 and row 5, column 2.
4. The “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino vertically on row 3, column 1 and row 4, column 1.
5. Row 7, column 2 has only one open neighbor, so its domino must run to row 6, column 2; the “=” region at the bottom-left needs every pip to match (3 of its 4 cells are already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–4 domino vertically on row 6, column 2 and row 7, column 2.
6. The “=” region at the top-right needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–1 domino vertically on row 1, column 4 and row 2, column 4.
7. The “=” region at the top-right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino horizontally on row 2, column 2 and row 2, column 3.
8. The 15 region at the top-left needs a total of exactly 15 (1 of its 3 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino vertically on row 1, column 1 and row 2, column 1.
9. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 15 region at the top-left needs a total of exactly 15 (2 of its 3 cells are already filled) — nothing else fits. Place the 4–5 domino horizontally on row 1, column 2 and row 1, column 3.
10. Row 3, column 2 has only one open neighbor, so its domino must run to row 4, column 2; the 15 region at the top-left needs a total of exactly 15 (2 of its 3 cells are already filled) — nothing else fits. Place the 2–5 domino vertically on row 3, column 2 and row 4, column 2.
11. The 15 region at the center needs a total of exactly 15 (1 of its 3 cells is already filled) — nothing else fits. Place the 4–4 domino horizontally on row 6, column 3 and row 6, column 4.
12. Row 5, column 3 has only one open neighbor, so its domino must run to row 5, column 4; the 15 region at the center needs a total of exactly 15 (2 of its 3 cells are already filled) — nothing else fits. Place the 2–6 domino horizontally on row 5, column 3 and row 5, column 4.