Pips answers for Monday, December 29, 2025

Start with the “=” region at the bottom-left: all 2 cells must show the same number, and only 4 or 5 appear on enough dominoes to fill it.

• the single-cell “>5” region at the left: 6
• the “=” region at the bottom-left: 4, 4
• the single-cell 1 region at the center: 1
• the 8 region at the right: 4, 4
• the single-cell “<3” region at the bottom-left: 2
• the “=” region at the bottom: 5, 5

1. The single-cell “>5” region at the left must total more than 5 — nothing else fits. Place the 4–6 domino horizontally on row 2, column 1 and row 2, column 2.
2. The single-cell 1 region at the center needs a total of exactly 1 — nothing else fits. Place the 1–4 domino vertically on row 1, column 3 and row 2, column 3.
3. The 8 region at the right needs a total of exactly 8 — nothing else fits. Place the 4–4 domino horizontally on row 2, column 4 and row 2, column 5.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “<3” region at the bottom-left must total less than 3 — nothing else fits. Place the 2–4 domino horizontally on row 3, column 1 and row 3, column 2.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the bottom needs every pip to match — nothing else fits. Place the 5–5 domino horizontally on row 3, column 3 and row 3, column 4.

Start with the 10 region at the top: only 4 + 6, or 5 + 5 can make it with these dominoes.

• the 10 region at the top: 4, 6
• the 10 region at the top: 4, 6
• the 10 region at the right: 2, 3, 5
• the single-cell “>0” region at the left: 1
• the 10 region at the left: 5, 5
• the 10 region at the right: 4, 6

1. The 10 region at the top needs a total of exactly 10 — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 1, column 3 and row 1, column 4.
2. The 10 region at the top needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 6–6 domino vertically on row 2, column 4 and row 3, column 4.
3. The 10 region at the right needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 3, column 5 and row 3, column 6.
4. The 10 region at the top needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino vertically on row 2, column 3 and row 3, column 3.
5. Row 1, column 6 has only one open neighbor, so its domino must run to row 2, column 6; the 10 region at the right needs a total of exactly 10 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 1, column 6 and row 2, column 6.
6. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell “>0” region at the left must total more than 0 — nothing else fits. Place the 1–5 domino horizontally on row 2, column 1 and row 2, column 2.
7. Row 3, column 2 has only one open neighbor, so its domino must run to row 4, column 2; the 10 region at the left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 3, column 2 and row 4, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the 12 region at the left: the only way to make it with these dominoes is 6 + 6.

• the “=” region at the top-left: 2, 2, 2
• the single-cell 3 region at the top-left: 3
• the “≠” region at the top-right: 0, 1, 2, 5
• the 20 region at the right: 5, 5, 5, 5
• the single-cell 6 region at the top-right: 6
• the 12 region at the left: 6, 6
• the single-cell “<3” region at the left: 2
• the 3 region at the left: 1, 1, 1
• the single-cell “>3” region at the right: 4
• the “=” region at the bottom-left: 3, 3, 3, 3, 3
• the 12 region at the right: 6, 6
• the single-cell “>3” region at the bottom-left: 4
• the “≠” region at the bottom-right: 1, 2, 4, 5

1. The 12 region at the left needs a total of exactly 12 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 4, column 1 and row 4, column 2.
2. The 12 region at the right needs a total of exactly 12 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 5, column 4 and row 6, column 4.
3. The 20 region at the right needs a total of exactly 20 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 5, column 5 and row 6, column 5.
4. The 3 region at the left needs a total of exactly 3 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino vertically on row 5, column 2 and row 6, column 2.
5. The “=” region at the bottom-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino vertically on row 5, column 1 and row 6, column 1.
6. The single-cell 6 region at the top-right needs a total of exactly 6 — nothing else fits. Place the 1–6 domino vertically on row 2, column 5 and row 3, column 5.
7. The 20 region at the right needs a total of exactly 20 (1 of its 4 cells is already filled) — nothing else fits. Place the 5–5 domino horizontally on row 4, column 4 and row 4, column 5.
8. The “=” region at the bottom-left needs every pip to match (1 of its 5 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 7, column 1 and row 7, column 2.
9. The “=” region at the bottom-left needs every pip to match (2 of its 5 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 8, column 1 and row 8, column 2.
10. Row 9, column 1 has only one open neighbor, so its domino must run to row 9, column 2; the “=” region at the bottom-left needs every pip to match (3 of its 5 cells are already filled) — nothing else fits. Place the 3–3 domino horizontally on row 9, column 1 and row 9, column 2.
11. The “≠” region at the top-right needs every pip to be different (1 of its 4 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 2, column 4 and row 3, column 4.
12. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 1, column 1 and row 1, column 2.
13. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the “=” region at the top-left needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino horizontally on row 2, column 1 and row 2, column 2.
14. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the “≠” region at the top-right needs every pip to be different (2 of its 4 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 1, column 4 and row 1, column 5.
15. The “≠” region at the bottom-right needs every pip to be different — 8 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 8, column 4 and row 8, column 5.
16. Row 9, column 4 has only one open neighbor, so its domino must run to row 9, column 5; the “≠” region at the bottom-right needs every pip to be different (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 9, column 4 and row 9, column 5.

This board has more than one valid layout; the steps follow the official answer.