Pips answers for Tuesday, January 27, 2026

Start with the “=” region at the bottom: all 3 cells must show the same number, and only 2s appear on enough dominoes to fill it.

• the single-cell “>5” region at the top: 6
• the “=” region at the center: 3, 3
• the “=” region at the bottom: 2, 2, 2
• the single-cell “>3” region at the bottom-right: 4

1. The single-cell “>5” region at the top must total more than 5 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino horizontally on row 1, column 1 and row 1, column 2.
2. The “=” region at the bottom needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–4 domino horizontally on row 4, column 3 and row 4, column 4.
3. The “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino vertically on row 2, column 2 and row 3, column 2.
4. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino horizontally on row 2, column 3 and row 2, column 4.
5. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 1; the “=” region at the bottom needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–2 domino horizontally on row 4, column 1 and row 4, column 2.

Start with the 12 region at the bottom: the only way to make it with these dominoes is 6 + 6.

• the 12 region at the top-right: 4, 4, 4
• the 5 region at the top: 0, 0, 1, 4
• the single-cell “<4” region at the top-right: 2
• the “=” region at the center: 1, 1
• the “<10” region at the bottom-left: 4, 4
• the 12 region at the bottom: 6, 6
• the “=” region at the bottom: 5, 5

1. The 5 region at the top needs a total of exactly 5 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–4 domino horizontally on row 3, column 4 and row 3, column 5.
2. The 5 region at the top needs a total of exactly 5 (1 of its 4 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino vertically on row 3, column 3 and row 4, column 3.
3. Row 2, column 3 has only one open neighbor, so its domino must run to row 1, column 3; the 5 region at the top needs a total of exactly 5 (3 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–4 domino vertically on row 1, column 3 and row 2, column 3.
4. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the 12 region at the top-right needs a total of exactly 12 (1 of its 3 cells is already filled) — nothing else fits. Place the 4–4 domino horizontally on row 1, column 4 and row 1, column 5.
5. Row 5, column 3 has only one open neighbor, so its domino must run to row 6, column 3; the “=” region at the center needs every pip to match — nothing else fits. Place the 1–1 domino vertically on row 5, column 3 and row 6, column 3.
6. The 12 region at the bottom needs a total of exactly 12 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino vertically on row 7, column 3 and row 8, column 3.
7. The 12 region at the bottom needs a total of exactly 12 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino horizontally on row 7, column 1 and row 7, column 2.
8. Row 8, column 1 has only one open neighbor, so its domino must run to row 8, column 2; the “<10” region at the bottom-left must total less than 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino horizontally on row 8, column 1 and row 8, column 2.

Start with the “>15” region at the bottom — it has the fewest pip combinations on the board, so the dominoes around it are the easiest to pin down.

• the “>5” region at the top-left: 2, 2, 2
• the “>9” region at the top: 4, 6
• the single-cell “>1” region at the top: 2
• the “>8” region at the center: 4, 5
• the single-cell “>0” region at the center: 1
• the single-cell “>0” region at the right: 1
• the “>8” region at the right: 3, 3, 3
• the single-cell “>1” region at the center: 2
• the single-cell “>0” region at the bottom-left: 1
• the “>15” region at the bottom: 5, 5, 6
• the single-cell “>0” region at the bottom: 1
• the “>9” region at the bottom-left: 4, 6

1. Row 6, column 1 has only one open neighbor, so its domino must run to row 6, column 2; the “>9” region at the bottom-left must total more than 9 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 6, column 1 and row 6, column 2.
2. The “>15” region at the bottom must total more than 15 — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 5, column 2 and row 5, column 3.
3. The “>15” region at the bottom must total more than 15 (1 of its 3 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 4, column 4 and row 5, column 4.
4. Row 6, column 4 has only one open neighbor, so its domino must run to row 6, column 3; the “>15” region at the bottom must total more than 15 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino horizontally on row 6, column 3 and row 6, column 4.
5. The “>8” region at the center must total more than 8 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 3, column 4 and row 3, column 5.
6. The “>9” region at the top must total more than 9 — nothing else fits. Place the 2–4 domino horizontally on row 2, column 4 and row 2, column 5.
7. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 3; the “>9” region at the top must total more than 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 1, column 3 and row 1, column 4.
8. The single-cell “>1” region at the center must total more than 1 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 4, column 5 and row 5, column 5.
9. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the “>5” region at the top-left must total more than 5 — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 1, column 1 and row 1, column 2.
10. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the “>5” region at the top-left must total more than 5 (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino horizontally on row 2, column 2 and row 2, column 3.
11. The “>8” region at the right must total more than 8 — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 3, column 6 and row 3, column 7.
12. Row 4, column 6 has only one open neighbor, so its domino must run to row 4, column 7; the “>8” region at the right must total more than 8 (1 of its 3 cells is already filled) — nothing else fits. Place the 3–3 domino horizontally on row 4, column 6 and row 4, column 7.

This board has more than one valid layout; the steps follow the official answer.