Pips answers for Wednesday, January 28, 2026

Start with the 8 region at the bottom-right: the only way to make it with these dominoes is 4 + 4.

• the 5 region at the top-left: 0, 5
• the “=” region at the center: 5, 5
• the single-cell 4 region at the right: 4
• the “=” region at the right: 1, 1
• the 8 region at the bottom-right: 4, 4

1. The 8 region at the bottom-right needs a total of exactly 8 — nothing else fits. Place the 4–4 domino horizontally on row 4, column 4 and row 4, column 5.
2. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the single-cell 4 region at the right needs a total of exactly 4 — nothing else fits. Place the 1–4 domino vertically on row 2, column 5 and row 3, column 5.
3. The “=” region at the center needs every pip to match — nothing else fits. Place the 1–5 domino horizontally on row 3, column 3 and row 3, column 4.
4. The 5 region at the top-left needs a total of exactly 5 — nothing else fits. Place the 5–5 domino horizontally on row 2, column 2 and row 2, column 3.
5. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the 5 region at the top-left needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–2 domino horizontally on row 1, column 1 and row 1, column 2.

Start with the 9 region at the left: only 3 + 6, or 4 + 5 can make it with these dominoes.

• the single-cell 3 region at the top-left: 3
• the “=” region at the top-right: 5, 5
• the single-cell 3 region at the top-right: 3
• the 9 region at the left: 4, 5
• the “>2” region at the left: 2, 6
• the single-cell “>5” region at the right: 6
• the single-cell 4 region at the right: 4
• the “=” region at the bottom: 1, 1

1. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the bottom needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 4, column 3 and row 4, column 4.
2. The single-cell 3 region at the top-right needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 1, column 5 and row 1, column 6.
3. The “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino vertically on row 2, column 5 and row 3, column 5.
4. The single-cell 3 region at the top-left needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 9 region at the left needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino horizontally on row 3, column 1 and row 3, column 2.
6. Row 2, column 2 has only one open neighbor, so its domino must run to row 1, column 2; the “>2” region at the left must total more than 2 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino vertically on row 1, column 2 and row 2, column 2.
7. Row 2, column 6 has only one open neighbor, so its domino must run to row 3, column 6; the single-cell “>5” region at the right must total more than 5 — nothing else fits. Place the 0–6 domino vertically on row 2, column 6 and row 3, column 6.

This board has more than one valid layout; the steps follow the official answer.

Start with the “>10” region at the right: the only way to make it with these dominoes is 5 + 6.

• the single-cell 3 region at the top-left: 3
• the 5 region at the top: 0, 5
• the 5 region at the top-right: 2, 3
• the “=” region at the top-left: 4, 4
• the 2 region at the top: 1, 1
• the “>10” region at the right: 5, 6
• the “≠” region at the left: 0, 1, 2, 5
• the “<2” region at the right: 0, 0

1. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 1, column 1 and row 2, column 1.
2. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino vertically on row 3, column 1 and row 4, column 1.
3. The “>10” region at the right must total more than 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 4, column 5 and row 5, column 5.
4. The 5 region at the top-right needs a total of exactly 5 — nothing else fits. Place the 2–6 domino vertically on row 2, column 5 and row 3, column 5.
5. The 5 region at the top needs a total of exactly 5 — nothing else fits. Place the 0–3 domino horizontally on row 1, column 4 and row 1, column 5.
6. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the 5 region at the top needs a total of exactly 5 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino vertically on row 1, column 3 and row 2, column 3.
7. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the 2 region at the top needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–1 domino vertically on row 3, column 3 and row 4, column 3.
8. The “≠” region at the left needs every pip to be different (1 of its 4 cells is already filled) — nothing else fits. Place the 0–0 domino horizontally on row 5, column 3 and row 5, column 4.
9. Row 5, column 1 has only one open neighbor, so its domino must run to row 5, column 2; the “≠” region at the left needs every pip to be different (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 5, column 1 and row 5, column 2.
10. Row 6, column 3 has only one open neighbor, so its domino must run to row 7, column 3 — nothing else fits. Place the 5–5 domino vertically on row 6, column 3 and row 7, column 3.

This board has more than one valid layout; the steps follow the official answer.