Pips answers for Sunday, June 7, 2026

Start with the “=” region at the bottom-right: all 4 cells must show the same number, and only 2s appear on enough dominoes to fill it.

• the “>13” region at the top: 5, 5, 6
• the single-cell 3 region at the top-right: 3
• the single-cell “>0” region at the left: 1
• the “=” region at the bottom-right: 2, 2, 2, 2
• the single-cell “<2” region at the bottom-right: 1

1. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 2–2 domino vertically on row 3, column 4 and row 4, column 4.
2. The “=” region at the bottom-right needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 1–2 domino horizontally on row 5, column 4 and row 5, column 5.
3. Row 5, column 3 has only one open neighbor, so its domino must run to row 5, column 2; the “=” region at the bottom-right needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 2–3 domino horizontally on row 5, column 2 and row 5, column 3.
4. The “>13” region at the top must total more than 13 — nothing else fits. Place the 3–6 domino horizontally on row 1, column 3 and row 1, column 4.
5. The “>13” region at the top must total more than 13 (1 of its 3 cells is already filled) — nothing else fits. Place the 1–5 domino vertically on row 2, column 2 and row 3, column 2.
6. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the “>13” region at the top must total more than 13 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–5 domino horizontally on row 1, column 1 and row 1, column 2.

Start with the 3 region at the left: the only way to make it with these dominoes is 1 + 2.

• the 3 region at the left: 1, 2
• the “=” region at the center: 0, 0
• the “=” region at the bottom-left: 4, 4
• the single-cell “>2” region at the left: 6
• the 3 region at the bottom: 1, 2
• the 3 region at the bottom-right: 1, 2
• the single-cell “>0” region at the right: 2

1. The “=” region at the center needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino horizontally on row 2, column 3 and row 2, column 4.
2. The 3 region at the bottom needs a total of exactly 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 3, column 2 and row 3, column 3.
3. The 3 region at the bottom-right needs a total of exactly 3 — nothing else fits. Place the 1–1 domino horizontally on row 4, column 3 and row 4, column 4.
4. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 5; the 3 region at the bottom-right needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–2 domino horizontally on row 3, column 4 and row 3, column 5.
5. The 3 region at the left needs a total of exactly 3 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–4 domino vertically on row 2, column 1 and row 3, column 1.
6. Row 2, column 2 has only one open neighbor, so its domino must run to row 1, column 2; the 3 region at the left needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–2 domino vertically on row 1, column 2 and row 2, column 2.
7. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino horizontally on row 4, column 1 and row 4, column 2.

Start with the 7 region at the top-right: only 1 + 6, or 2 + 5, or 3 + 4 can make it with these dominoes.

• the 6 region at the top-left: 1, 5
• the “=” region at the top: 3, 3
• the 7 region at the top-right: 3, 4
• the 7 region at the top-right: 3, 4
• the 6 region at the left: 1, 5
• the “=” region at the left: 6, 6
• the “=” region at the right: 6, 6
• the 6 region at the bottom-left: 2, 4
• the single-cell 6 region at the bottom: 6
• the 6 region at the bottom-left: 2, 4

1. The “=” region at the left needs every pip to match — 7 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 3, column 2 and row 3, column 3.
2. The 6 region at the bottom-left needs a total of exactly 6 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 4, column 3 and row 5, column 3.
3. The 6 region at the bottom-left needs a total of exactly 6 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 5, column 1 and row 5, column 2.
4. The 6 region at the left needs a total of exactly 6 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 3, column 1 and row 4, column 1.
5. The 6 region at the top-left needs a total of exactly 6 — nothing else fits. Place the 1–1 domino vertically on row 1, column 1 and row 2, column 1.
6. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 6 region at the top-left needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino horizontally on row 1, column 2 and row 1, column 3.
7. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 1, column 4 and row 1, column 5.
8. Row 1, column 6 has only one open neighbor, so its domino must run to row 1, column 7; the 7 region at the top-right needs a total of exactly 7 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 1, column 6 and row 1, column 7.
9. Row 2, column 7 has only one open neighbor, so its domino must run to row 3, column 7; the 7 region at the top-right needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino vertically on row 2, column 7 and row 3, column 7.
10. Row 4, column 7 has only one open neighbor, so its domino must run to row 5, column 7; the “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 4, column 7 and row 5, column 7.

This board has more than one valid layout; the steps follow the official answer.