Pips answers for Monday, June 8, 2026

Start with the 10 region at the right: the only way to make it with these dominoes is 5 + 5.

• the 8 region at the left: 2, 6
• the 10 region at the right: 5, 5
• the 5 region at the bottom-right: 2, 3
• the single-cell “<1” region at the bottom: 0

1. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the single-cell “<1” region at the bottom must total less than 1 — nothing else fits. Place the 0–2 domino horizontally on row 4, column 3 and row 4, column 4.
2. The 10 region at the right needs a total of exactly 10 — nothing else fits. Place the 3–5 domino vertically on row 2, column 4 and row 3, column 4.
3. Row 2, column 3 has only one open neighbor, so its domino must run to row 1, column 3; the 10 region at the right needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino vertically on row 1, column 3 and row 2, column 3.
4. The 8 region at the left needs a total of exactly 8 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 8 region at the left needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino horizontally on row 3, column 1 and row 3, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the 7 region at the left: only 1 + 6, or 2 + 5, or 3 + 4 can make it with these dominoes.

• the 11 region at the top-right: 3, 4, 4
• the 7 region at the left: 1, 6
• the “=” region at the bottom-left: 0, 0
• the “=” region at the center: 0, 0
• the single-cell 5 region at the bottom-left: 5
• the “>8” region at the bottom: 4, 5
• the single-cell “>0” region at the bottom-right: 1

1. The “>8” region at the bottom must total more than 8 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–5 domino horizontally on row 4, column 4 and row 4, column 5.
2. The single-cell 5 region at the bottom-left needs a total of exactly 5 — nothing else fits. Place the 0–5 domino horizontally on row 4, column 1 and row 4, column 2.
3. The 11 region at the top-right needs a total of exactly 11 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino horizontally on row 1, column 4 and row 1, column 5.
4. The “=” region at the center needs every pip to match — nothing else fits. Place the 0–3 domino vertically on row 2, column 4 and row 3, column 4.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino horizontally on row 3, column 1 and row 3, column 2.
6. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the 7 region at the left needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino horizontally on row 2, column 2 and row 2, column 3.
7. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino vertically on row 3, column 3 and row 4, column 3.

Start with the 10 region at the bottom: only 4 + 6, or 5 + 5 can make it with these dominoes.

• the single-cell 4 region at the top-left: 4
• the “=” region at the top: 1, 1, 1, 1, 1
• the single-cell 0 region at the top-right: 0
• the single-cell “>4” region at the top-left: 5
• the single-cell “<4” region at the top-left: 3
• the single-cell 4 region at the top: 4
• the 6 region at the top-right: 3, 3
• the single-cell “>2” region at the top-right: 6
• the “=” region at the left: 0, 0, 0, 0
• the “≠” region at the bottom-right: 0, 2, 3, 4, 5
• the single-cell 6 region at the bottom: 6
• the single-cell 2 region at the bottom-right: 2
• the single-cell 2 region at the bottom-left: 2
• the single-cell 3 region at the bottom-left: 3
• the 10 region at the bottom: 5, 5
• the single-cell 4 region at the bottom-right: 4

1. The single-cell 3 region at the bottom-left needs a total of exactly 3 — nothing else fits. Place the 3–5 domino horizontally on row 5, column 2 and row 5, column 3.
2. The “≠” region at the bottom-right needs every pip to be different — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 5, column 4 and row 5, column 5.
3. The “≠” region at the bottom-right needs every pip to be different (1 of its 5 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino horizontally on row 4, column 5 and row 4, column 6.
4. Row 5, column 6 has only one open neighbor, so its domino must run to row 5, column 7; the “≠” region at the bottom-right needs every pip to be different (2 of its 5 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino horizontally on row 5, column 6 and row 5, column 7.
5. The “≠” region at the bottom-right needs every pip to be different (3 of its 5 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino vertically on row 3, column 7 and row 4, column 7.
6. The “=” region at the left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino vertically on row 4, column 1 and row 5, column 1.
7. The “=” region at the left needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 2, column 1 and row 3, column 1.
8. The “=” region at the left needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 0–4 domino vertically on row 2, column 3 and row 3, column 3.
9. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell 4 region at the top-left needs a total of exactly 4 — nothing else fits. Place the 1–4 domino horizontally on row 1, column 1 and row 1, column 2.
10. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top needs every pip to match (1 of its 5 cells is already filled) — nothing else fits. Place the 1–1 domino horizontally on row 1, column 3 and row 1, column 4.
11. The “=” region at the top needs every pip to match (3 of its 5 cells are already filled) — nothing else fits. Place the 0–1 domino horizontally on row 1, column 5 and row 1, column 6.
12. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “<4” region at the top-left must total less than 4 — nothing else fits. Place the 0–3 domino vertically on row 2, column 2 and row 3, column 2.
13. Row 2, column 4 has only one open neighbor, so its domino must run to row 2, column 5; the “=” region at the top needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 1–3 domino horizontally on row 2, column 4 and row 2, column 5.
14. The 6 region at the top-right needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–3 domino vertically on row 2, column 6 and row 3, column 6.
15. Row 2, column 7 has only one open neighbor, so its domino must run to row 1, column 7; the single-cell “>2” region at the top-right must total more than 2 — nothing else fits. Place the 2–6 domino vertically on row 1, column 7 and row 2, column 7.