Pips answers for Tuesday, June 9, 2026

Start with the 11 region at the top-right: the only way to make it with these dominoes is 5 + 6.

• the 11 region at the top-right: 5, 6
• the single-cell 4 region at the center: 4
• the 4 region at the bottom: 2, 2
• the “=” region at the bottom-right: 4, 4
• the “=” region at the bottom-left: 6, 6

1. The 4 region at the bottom needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 3, column 3 and row 4, column 3.
2. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the “=” region at the bottom-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino vertically on row 5, column 1 and row 6, column 1.
3. The 11 region at the top-right needs a total of exactly 11 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 1, column 5 and row 2, column 5.
4. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the 11 region at the top-right needs a total of exactly 11 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino vertically on row 3, column 5 and row 4, column 5.
5. Row 5, column 3 has only one open neighbor, so its domino must run to row 6, column 3; the 4 region at the bottom needs a total of exactly 4 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 5, column 3 and row 6, column 3.
6. Row 5, column 5 has only one open neighbor, so its domino must run to row 6, column 5; the “=” region at the bottom-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 5, column 5 and row 6, column 5.

This board has more than one valid layout; the steps follow the official answer.

Start with the 9 region at the bottom-left: the only way to make it with these dominoes is 3 + 6.

• the single-cell 5 region at the top-left: 5
• the single-cell 3 region at the top: 3
• the “=” region at the left: 1, 1
• the “=” region at the right: 1, 1
• the “=” region at the center: 5, 5, 5
• the 9 region at the bottom-left: 3, 6
• the “>9” region at the bottom-right: 6, 6

1. The single-cell 3 region at the top needs a total of exactly 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–3 domino vertically on row 1, column 2 and row 2, column 2.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell 5 region at the top-left needs a total of exactly 5 — nothing else fits. Place the 1–5 domino vertically on row 1, column 1 and row 2, column 1.
3. The 9 region at the bottom-left needs a total of exactly 9 — 8 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino vertically on row 3, column 1 and row 4, column 1.
4. The 9 region at the bottom-left needs a total of exactly 9 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino horizontally on row 4, column 2 and row 4, column 3.
5. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 3; the “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 3, column 2 and row 3, column 3.
6. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the right needs every pip to match — nothing else fits. Place the 1–1 domino horizontally on row 2, column 3 and row 2, column 4.
7. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 5–6 domino vertically on row 3, column 4 and row 4, column 4.

Start with the “>10” region at the top: only 5 + 6, or 6 + 6 can make it with these dominoes.

• the 12 region at the top-left: 3, 4, 5
• the “>10” region at the top: 5, 6
• the single-cell “>4” region at the top: 5
• the “<4” region at the top: 1, 2
• the single-cell 4 region at the top-left: 4
• the “>10” region at the right: 6, 6
• the “≠” region at the center: 0, 1, 4, 6
• the “=” region at the bottom-right: 3, 3, 3
• the single-cell “<4” region at the right: 0
• the 10 region at the bottom-right: 4, 6

1. The single-cell “>4” region at the top must total more than 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino horizontally on row 1, column 5 and row 1, column 6.
2. Row 8, column 7 has only one open neighbor, so its domino must run to row 8, column 8; the 10 region at the bottom-right needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 8, column 7 and row 8, column 8.
3. The 12 region at the top-left needs a total of exactly 12 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 2, column 1 and row 3, column 1.
4. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 12 region at the top-left needs a total of exactly 12 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 1, column 1 and row 1, column 2.
5. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 6, column 8 and row 7, column 8.
6. The “>10” region at the right must total more than 10 — nothing else fits. Place the 6–6 domino horizontally on row 4, column 8 and row 4, column 9.
7. Row 5, column 8 has only one open neighbor, so its domino must run to row 5, column 9; the “=” region at the bottom-right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–3 domino horizontally on row 5, column 8 and row 5, column 9.
8. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 3; the “>10” region at the top must total more than 10 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino horizontally on row 1, column 3 and row 1, column 4.
9. Row 2, column 6 has only one open neighbor, so its domino must run to row 3, column 6; the “<4” region at the top must total less than 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 2, column 6 and row 3, column 6.
10. The “≠” region at the center needs every pip to be different — 8 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 5, column 4 and row 5, column 5.
11. Row 6, column 4 has only one open neighbor, so its domino must run to row 6, column 5; the “≠” region at the center needs every pip to be different (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 6, column 4 and row 6, column 5.

This board has more than one valid layout; the steps follow the official answer.