Pips answers for Wednesday, June 17, 2026

Start with the “=” region at the right: all 4 cells must show the same number, and only 3s appear on enough dominoes to fill it.

• the “=” region at the top-left: 5, 5, 5
• the “=” region at the right: 3, 3, 3, 3
• the single-cell “>2” region at the top-right: 4
• the “<9” region at the bottom-left: 2, 6

1. The “=” region at the right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 2, column 4 and row 3, column 4.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the “=” region at the top-left needs every pip to match — nothing else fits. Place the 5–5 domino horizontally on row 1, column 1 and row 1, column 2.
3. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the “=” region at the right needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 3–4 domino horizontally on row 1, column 4 and row 1, column 5.
4. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 5–6 domino vertically on row 2, column 2 and row 3, column 2.
5. Row 4, column 4 has only one open neighbor, so its domino must run to row 4, column 5; the “=” region at the right needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 1–3 domino horizontally on row 4, column 4 and row 4, column 5.
6. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 1; the “<9” region at the bottom-left must total less than 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino horizontally on row 4, column 1 and row 4, column 2.

Start with the 9 region at the top-left: only 3 + 6, or 4 + 5 can make it with these dominoes.

• the 9 region at the top-left: 4, 5
• the “=” region at the top-left: 6, 6
• the “=” region at the center: 0, 0
• the 4 region at the center: 1, 3
• the single-cell “<2” region at the right: 0
• the 9 region at the bottom-right: 4, 5
• the “=” region at the bottom-right: 2, 2

1. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino horizontally on row 5, column 5 and row 5, column 6.
2. The 9 region at the bottom-right needs a total of exactly 9 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–5 domino vertically on row 3, column 6 and row 4, column 6.
3. The 4 region at the center needs a total of exactly 4 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–4 domino horizontally on row 4, column 4 and row 4, column 5.
4. The “=” region at the center needs every pip to match — nothing else fits. Place the 0–3 domino horizontally on row 3, column 3 and row 3, column 4.
5. The “=” region at the top-left needs every pip to match — nothing else fits. Place the 0–6 domino horizontally on row 2, column 2 and row 2, column 3.
6. The 9 region at the top-left needs a total of exactly 9 — nothing else fits. Place the 5–6 domino horizontally on row 1, column 1 and row 1, column 2.
7. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the 9 region at the top-left needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 2, column 1 and row 3, column 1.

Start with the 7 region at the left: only 1 + 6, or 2 + 5, or 3 + 4 can make it with these dominoes.

• the single-cell 6 region at the top-left: 6
• the “=” region at the top: 0, 0, 0, 0
• the single-cell “<4” region at the top: 3
• the “>9” region at the top-left: 5, 6
• the single-cell “>4” region at the top: 5
• the 7 region at the left: 2, 5
• the single-cell 4 region at the center: 4
• the single-cell 2 region at the left: 2
• the 6 region at the center: 2, 4
• the single-cell 6 region at the center: 6
• the 6 region at the right: 1, 1, 4
• the 6 region at the bottom-right: 3, 3
• the single-cell 0 region at the right: 0
• the “=” region at the bottom-right: 2, 2
• the 6 region at the bottom-right: 3, 3
• the 6 region at the bottom-right: 1, 5

1. The “>9” region at the top-left must total more than 9 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–6 domino vertically on row 1, column 1 and row 2, column 1.
2. The 6 region at the center needs a total of exactly 6 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino horizontally on row 5, column 5 and row 5, column 6.
3. The single-cell 4 region at the center needs a total of exactly 4 — nothing else fits. Place the 2–4 domino vertically on row 4, column 4 and row 5, column 4.
4. The “=” region at the top needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino vertically on row 1, column 4 and row 2, column 4.
5. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 5; the “=” region at the top needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 0–5 domino horizontally on row 3, column 4 and row 3, column 5.
6. Row 1, column 5 has only one open neighbor, so its domino must run to row 1, column 6; the “=” region at the top needs every pip to match (3 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino horizontally on row 1, column 5 and row 1, column 6.
7. The single-cell 0 region at the right needs a total of exactly 0 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino vertically on row 7, column 9 and row 8, column 9.
8. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “>9” region at the top-left must total more than 9 (1 of its 2 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino vertically on row 3, column 1 and row 4, column 1.
9. Row 5, column 1 has only one open neighbor, so its domino must run to row 5, column 2; the 7 region at the left needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino horizontally on row 5, column 1 and row 5, column 2.
10. Row 9, column 9 has only one open neighbor, so its domino must run to row 10, column 9; the “=” region at the bottom-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 9, column 9 and row 10, column 9.
11. The 6 region at the bottom-right needs a total of exactly 6 — nothing else fits. Place the 3–5 domino horizontally on row 10, column 7 and row 10, column 8.
12. The 6 region at the right needs a total of exactly 6 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–1 domino horizontally on row 6, column 8 and row 6, column 9.
13. Row 6, column 7 has only one open neighbor, so its domino must run to row 7, column 7; the 6 region at the right needs a total of exactly 6 (2 of its 3 cells are already filled) — nothing else fits. Place the 3–4 domino vertically on row 6, column 7 and row 7, column 7.
14. Row 8, column 7 has only one open neighbor, so its domino must run to row 9, column 7; the 6 region at the bottom-right needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–3 domino vertically on row 8, column 7 and row 9, column 7.