Pips answers for Thursday, June 18, 2026

Start with the “=” region at the top: all 2 cells must show the same number, and only 1 or 3 or 5 or 6 appear on enough dominoes to fill it.

• the “=” region at the top: 1, 1
• the single-cell “>2” region at the top: 6
• the single-cell “>2” region at the left: 4
• the single-cell 5 region at the left: 5
• the “=” region at the right: 3, 3
• the single-cell 5 region at the right: 5
• the single-cell “>3” region at the bottom: 6
• the single-cell 5 region at the bottom: 5

1. The “=” region at the right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 2, column 5 and row 2, column 6.
2. The “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino horizontally on row 2, column 3 and row 2, column 4.
3. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino horizontally on row 1, column 3 and row 1, column 4.
4. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell “>2” region at the left must total more than 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 2, column 1 and row 2, column 2.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the single-cell “>3” region at the bottom must total more than 3 — nothing else fits. Place the 5–6 domino horizontally on row 3, column 3 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 1 region at the top-right: the only way to make it with these dominoes is 0 + 1.

• the 7 region at the top-left: 3, 4
• the 1 region at the top-right: 0, 1
• the 9 region at the left: 4, 5
• the 8 region at the right: 3, 5
• the 8 region at the bottom: 2, 3, 3
• the single-cell “>4” region at the bottom: 6

1. The 8 region at the bottom needs a total of exactly 8 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino vertically on row 4, column 4 and row 5, column 4.
2. The 1 region at the top-right needs a total of exactly 1 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–5 domino vertically on row 2, column 6 and row 3, column 6.
3. Row 2, column 7 has only one open neighbor, so its domino must run to row 1, column 7; the 1 region at the top-right needs a total of exactly 1 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino vertically on row 1, column 7 and row 2, column 7.
4. Row 4, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the 8 region at the bottom needs a total of exactly 8 (1 of its 3 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 3, column 5 and row 4, column 5.
5. The 9 region at the left needs a total of exactly 9 — nothing else fits. Place the 3–5 domino vertically on row 3, column 3 and row 4, column 3.
6. The 7 region at the top-left needs a total of exactly 7 — nothing else fits. Place the 4–4 domino vertically on row 2, column 2 and row 3, column 2.
7. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the 7 region at the top-left needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino vertically on row 1, column 1 and row 2, column 1.

Start with the 10 region at the top-left: only 4 + 6, or 5 + 5 can make it with these dominoes.

• the “=” region at the top-left: 3, 3
• the 10 region at the top-left: 4, 6
• the “>10” region at the top-left: 5, 6
• the “<3” region at the left: 0, 2
• the “=” region at the center: 0, 0, 0, 0
• the single-cell “<4” region at the right: 3
• the 6 region at the bottom-left: 1, 5
• the “=” region at the bottom: 2, 2, 2, 2, 2
• the “=” region at the bottom-right: 1, 1, 1, 1
• the single-cell “<3” region at the right: 0
• the single-cell “>4” region at the bottom: 5
• the 10 region at the bottom-left: 4, 6
• the single-cell “>4” region at the bottom-right: 5

1. The 10 region at the top-left needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 1, column 3 and row 2, column 3.
2. The 10 region at the top-left needs a total of exactly 10 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 1, column 1 and row 1, column 2.
3. The “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino horizontally on row 2, column 1 and row 2, column 2.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “<3” region at the left must total less than 3 — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 3, column 1 and row 4, column 1.
5. The 10 region at the bottom-left needs a total of exactly 10 — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 5, column 3 and row 6, column 3.
6. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 2–6 domino vertically on row 5, column 4 and row 6, column 4.
7. The “=” region at the bottom needs every pip to match (1 of its 5 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 5, column 5 and row 5, column 6.
8. The 6 region at the bottom-left needs a total of exactly 6 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 3, column 3 and row 4, column 3.
9. The “=” region at the center needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 0–0 domino horizontally on row 3, column 4 and row 3, column 5.
10. Row 4, column 4 has only one open neighbor, so its domino must run to row 4, column 5; the “=” region at the bottom needs every pip to match (2 of its 5 cells are already filled) — nothing else fits. Place the 2–2 domino horizontally on row 4, column 4 and row 4, column 5.
11. The “=” region at the bottom needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 1–2 domino horizontally on row 4, column 6 and row 4, column 7.
12. The “=” region at the bottom-right needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 0–1 domino horizontally on row 4, column 8 and row 4, column 9.
13. Row 3, column 6 has only one open neighbor, so its domino must run to row 3, column 7; the “=” region at the center needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–3 domino horizontally on row 3, column 6 and row 3, column 7.
14. The “=” region at the bottom-right needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 1–5 domino vertically on row 5, column 7 and row 6, column 7.
15. Row 5, column 8 has only one open neighbor, so its domino must run to row 6, column 8; the “=” region at the bottom-right needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 1–3 domino vertically on row 5, column 8 and row 6, column 8.

This board has more than one valid layout; the steps follow the official answer.