Pips answers for Saturday, June 20, 2026

Start with the “=” region at the top: all 3 cells must show the same number, and only 2s appear on enough dominoes to fill it.

• the “=” region at the top: 2, 2, 2
• the “=” region at the left: 0, 0
• the single-cell “<5” region at the center: 3
• the 6 region at the right: 1, 5

1. The “=” region at the top needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino horizontally on row 1, column 3 and row 1, column 4.
2. The “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 2–5 domino horizontally on row 2, column 4 and row 2, column 5.
3. Row 2, column 6 has only one open neighbor, so its domino must run to row 3, column 6; the 6 region at the right needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–1 domino vertically on row 2, column 6 and row 3, column 6.
4. The “=” region at the left needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino horizontally on row 2, column 2 and row 2, column 3.
5. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 2, column 1 and row 3, column 1.

Start with the “=” region at the top-left: all 3 cells must show the same number, and only 1 or 3 appear on enough dominoes to fill it.

• the “=” region at the top-left: 3, 3, 3
• the single-cell 3 region at the top-right: 3
• the single-cell “>3” region at the left: 5
• the “=” region at the right: 1, 1, 1
• the single-cell “>3” region at the right: 6
• the “>2” region at the bottom: 4, 6
• the “=” region at the bottom-right: 0, 0

1. The single-cell 3 region at the top-right needs a total of exactly 3 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 1, column 3 and row 1, column 4.
2. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 1, column 2 and row 2, column 2.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 3–5 domino vertically on row 1, column 1 and row 2, column 1.
4. The “=” region at the right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 2, column 3 and row 2, column 4.
5. The “=” region at the right needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 3, column 4 and row 4, column 4.
6. The “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–4 domino horizontally on row 3, column 2 and row 3, column 3.
7. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “>2” region at the bottom must total more than 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino horizontally on row 4, column 2 and row 4, column 3.

This board has more than one valid layout; the steps follow the official answer.

Start with the 1 region at the top-left: the only way to make it with these dominoes is 0 + 1.

• the “=” region at the top-left: 3, 3
• the single-cell “<3” region at the top-left: 2
• the 1 region at the top-left: 0, 1
• the single-cell “>3” region at the top-right: 4
• the 11 region at the top-left: 5, 6
• the 7 region at the top: 2, 5
• the 1 region at the top-right: 0, 1
• the 5 region at the left: 1, 4
• the single-cell “<3” region at the right: 2
• the single-cell “<3” region at the left: 2
• the 10 region at the left: 4, 6
• the single-cell “>4” region at the right: 6
• the “=” region at the bottom-right: 3, 3, 3
• the single-cell “>2” region at the bottom-left: 3
• the single-cell “<2” region at the bottom: 0
• the “>10” region at the bottom-right: 6, 6
• the single-cell 1 region at the bottom-right: 1
• the “>9” region at the bottom: 4, 6

1. The 1 region at the top-right needs a total of exactly 1 — nothing else fits. Place the 1–2 domino vertically on row 4, column 8 and row 5, column 8.
2. Row 7, column 6 has only one open neighbor, so its domino must run to row 8, column 6; the single-cell “>4” region at the right must total more than 4 — nothing else fits. Place the 6–6 domino vertically on row 7, column 6 and row 8, column 6.
3. Row 7, column 8 has only one open neighbor, so its domino must run to row 8, column 8; the “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 3–3 domino vertically on row 7, column 8 and row 8, column 8.
4. Row 9, column 6 has only one open neighbor, so its domino must run to row 9, column 7; the “>10” region at the bottom-right must total more than 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino horizontally on row 9, column 6 and row 9, column 7.
5. The 1 region at the top-left needs a total of exactly 1 — nothing else fits. Place the 0–6 domino horizontally on row 3, column 1 and row 3, column 2.
6. Row 2, column 8 has only one open neighbor, so its domino must run to row 3, column 8; the single-cell “>3” region at the top-right must total more than 3 — nothing else fits. Place the 0–4 domino vertically on row 2, column 8 and row 3, column 8.
7. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 1, column 1 and row 2, column 1.
8. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 1, column 2 and row 1, column 3.
9. Row 9, column 8 has only one open neighbor, so its domino must run to row 10, column 8; the “=” region at the bottom-right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino vertically on row 9, column 8 and row 10, column 8.
10. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the 11 region at the top-left needs a total of exactly 11 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 3, column 3 and row 4, column 3.
11. Row 5, column 3 has only one open neighbor, so its domino must run to row 6, column 3; the 5 region at the left needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino vertically on row 5, column 3 and row 6, column 3.
12. Row 6, column 1 has only one open neighbor, so its domino must run to row 6, column 2; the single-cell “<3” region at the left must total less than 3 — nothing else fits. Place the 2–6 domino horizontally on row 6, column 1 and row 6, column 2.
13. Row 8, column 3 has only one open neighbor, so its domino must run to row 8, column 4; the single-cell “>2” region at the bottom-left must total more than 2 — nothing else fits. Place the 0–3 domino horizontally on row 8, column 3 and row 8, column 4.
14. Row 3, column 5 has only one open neighbor, so its domino must run to row 3, column 6; the 7 region at the top needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 3, column 5 and row 3, column 6.
15. Row 10, column 3 has only one open neighbor, so its domino must run to row 10, column 4; the “>9” region at the bottom must total more than 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 10, column 3 and row 10, column 4.

This board has more than one valid layout; the steps follow the official answer.