Pips answers for Friday, June 19, 2026

Start with the “=” region at the right: all 3 cells must show the same number, and only 5s appear on enough dominoes to fill it.

• the single-cell “<1” region at the top-right: 0
• the “=” region at the center: 3, 3
• the “=” region at the right: 5, 5, 5
• the single-cell “<1” region at the bottom-left: 0

1. The “=” region at the right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–5 domino vertically on row 1, column 5 and row 2, column 5.
2. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the single-cell “<1” region at the bottom-left must total less than 1 — nothing else fits. Place the 0–2 domino horizontally on row 4, column 1 and row 4, column 2.
3. The “=” region at the right needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–5 domino horizontally on row 2, column 3 and row 2, column 4.
4. The “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino horizontally on row 3, column 2 and row 3, column 3.
5. Row 3, column 5 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–5 domino horizontally on row 3, column 4 and row 3, column 5.

Start with the 12 region at the top: the only way to make it with these dominoes is 6 + 6.

• the single-cell “<2” region at the top: 1
• the 12 region at the top: 6, 6
• the “=” region at the bottom: 3, 3
• the “=” region at the bottom-left: 2, 2
• the “=” region at the bottom: 5, 5
• the single-cell “<1” region at the bottom-right: 0
• the single-cell “>4” region at the bottom-left: 6
• the “=” region at the bottom-right: 4, 4
• the single-cell “<2” region at the bottom-right: 1

1. The 12 region at the top needs a total of exactly 12 — nothing else fits. Place the 1–6 domino vertically on row 1, column 3 and row 2, column 3.
2. The single-cell “<1” region at the bottom-right must total less than 1 — nothing else fits. Place the 0–3 domino horizontally on row 5, column 4 and row 5, column 5.
3. Row 4, column 4 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino horizontally on row 4, column 3 and row 4, column 4.
4. The “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 1–4 domino horizontally on row 6, column 5 and row 6, column 6.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 1, column 4; the 12 region at the top needs a total of exactly 12 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino vertically on row 1, column 4 and row 2, column 4.
6. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 4–5 domino horizontally on row 6, column 3 and row 6, column 4.
7. The “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 2–5 domino horizontally on row 5, column 2 and row 5, column 3.
8. Row 6, column 1 has only one open neighbor, so its domino must run to row 6, column 2; the single-cell “>4” region at the bottom-left must total more than 4 — nothing else fits. Place the 2–6 domino horizontally on row 6, column 1 and row 6, column 2.

Start with the 9 region at the top-right: only 3 + 6, or 4 + 5 can make it with these dominoes.

• the “>9” region at the top-left: 5, 5
• the 9 region at the top-right: 3, 6
• the single-cell 0 region at the top-left: 0
• the “=” region at the top-left: 4, 4
• the “=” region at the left: 1, 1, 1
• the “=” region at the center: 2, 2, 2
• the “=” region at the right: 1, 1
• the single-cell 5 region at the right: 5
• the 9 region at the left: 2, 3, 4
• the single-cell 3 region at the center: 3
• the “=” region at the right: 6, 6
• the “>9” region at the bottom-left: 5, 6
• the 9 region at the bottom-right: 4, 5
• the single-cell 2 region at the bottom-left: 2
• the single-cell 0 region at the bottom: 0

1. Row 7, column 2 has only one open neighbor, so its domino must run to row 7, column 3; the single-cell 2 region at the bottom-left needs a total of exactly 2 — nothing else fits. Place the 2–6 domino horizontally on row 7, column 2 and row 7, column 3.
2. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 2, column 1 and row 2, column 2.
3. Row 7, column 6 has only one open neighbor, so its domino must run to row 7, column 7; the single-cell 0 region at the bottom needs a total of exactly 0 — nothing else fits. Place the 0–5 domino horizontally on row 7, column 6 and row 7, column 7.
4. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the “>9” region at the top-left must total more than 9 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino horizontally on row 1, column 2 and row 1, column 3.
5. The “=” region at the right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 3, column 8 and row 3, column 9.
6. The “=” region at the left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 2, column 3 and row 3, column 3.
7. The “=” region at the right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 5, column 7 and row 6, column 7.
8. Row 3, column 2 has only one open neighbor, so its domino must run to row 4, column 2; the “=” region at the left needs every pip to match (1 of its 3 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 3, column 2 and row 4, column 2.
9. The “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 3, column 4 and row 3, column 5.
10. The “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino vertically on row 3, column 6 and row 4, column 6.
11. Row 3, column 7 has only one open neighbor, so its domino must run to row 4, column 7; the “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino vertically on row 3, column 7 and row 4, column 7.
12. The 9 region at the left needs a total of exactly 9 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 4, column 3 and row 4, column 4.
13. Row 5, column 3 has only one open neighbor, so its domino must run to row 6, column 3; the 9 region at the left needs a total of exactly 9 (2 of its 3 cells are already filled) — nothing else fits. Place the 4–5 domino vertically on row 5, column 3 and row 6, column 3.
14. Row 1, column 8 has only one open neighbor, so its domino must run to row 2, column 8; the 9 region at the top-right needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino vertically on row 1, column 8 and row 2, column 8.

This board has more than one valid layout; the steps follow the official answer.