Pips answers for Saturday, August 8, 2026

Start with the “=” region at the top-left: all 3 cells must show the same number, and only 0s appear on enough dominoes to fill it.

• the “=” region at the top-left: 0, 0, 0
• the 6 region at the center: 1, 5
• the single-cell “>5” region at the bottom-left: 6
• the 6 region at the bottom: 2, 4
• the single-cell “<5” region at the bottom-right: 3

1. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the “=” region at the top-left needs every pip to match — nothing else fits. Place the 0–0 domino horizontally on row 1, column 1 and row 1, column 2.
2. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–5 domino vertically on row 2, column 2 and row 3, column 2.
3. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the single-cell “>5” region at the bottom-left must total more than 5 — nothing else fits. Place the 2–6 domino horizontally on row 4, column 1 and row 4, column 2.
4. The 6 region at the center needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino horizontally on row 3, column 3 and row 3, column 4.
5. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the 6 region at the bottom needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino horizontally on row 4, column 3 and row 4, column 4.

Start with the 6 region at the bottom: only 0 + 6, or 1 + 5 can make it with these dominoes.

• the “≠” region at the top: 1, 3
• the “=” region at the left: 1, 1
• the single-cell “>3” region at the center: 5
• the single-cell “<3” region at the left: 0
• the “>6” region at the center: 6, 6
• the 6 region at the bottom-right: 2, 2, 2
• the single-cell “<2” region at the bottom-left: 0
• the 6 region at the bottom: 0, 6

1. The “=” region at the left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 2, column 2 and row 2, column 3.
2. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “<3” region at the left must total less than 3 — nothing else fits. Place the 0–1 domino horizontally on row 3, column 1 and row 3, column 2.
3. The 6 region at the bottom needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino horizontally on row 4, column 2 and row 4, column 3.
4. The 6 region at the bottom-right needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 4, column 4 and row 4, column 5.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “>6” region at the center must total more than 6 — nothing else fits. Place the 6–6 domino horizontally on row 3, column 3 and row 3, column 4.
6. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “≠” region at the top needs every pip to be different — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 1, column 4 and row 2, column 4.
7. Row 3, column 5 has only one open neighbor, so its domino must run to row 3, column 6; the 6 region at the bottom-right needs a total of exactly 6 (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino horizontally on row 3, column 5 and row 3, column 6.

This board has more than one valid layout; the steps follow the official answer.

Start with the 0 region at the top: the only way to make it with these dominoes is 0 + 0.

• the single-cell “>3” region at the top-left: 6
• the “=” region at the top-left: 5, 5, 5
• the 0 region at the top: 0, 0
• the single-cell “>3” region at the top: 4
• the single-cell 3 region at the top-left: 3
• the “=” region at the left: 4, 4
• the “=” region at the center: 6, 6, 6, 6, 6, 6
• the single-cell 4 region at the center: 4
• the “=” region at the bottom-left: 2, 2, 2, 2, 2, 2
• the single-cell 3 region at the right: 3
• the 3 region at the bottom-right: 1, 2
• the single-cell “<3” region at the bottom: 1
• the single-cell “<3” region at the bottom-left: 0
• the 11 region at the bottom: 3, 3, 5
• the single-cell “<3” region at the bottom-right: 0

1. The 0 region at the top needs a total of exactly 0 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino horizontally on row 1, column 4 and row 1, column 5.
2. The 3 region at the bottom-right needs a total of exactly 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–3 domino vertically on row 5, column 7 and row 6, column 7.
3. Row 7, column 7 has only one open neighbor, so its domino must run to row 8, column 7; the 3 region at the bottom-right needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino vertically on row 7, column 7 and row 8, column 7.
4. The “=” region at the top-left needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino vertically on row 1, column 3 and row 2, column 3.
5. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell “>3” region at the top-left must total more than 3 — nothing else fits. Place the 5–6 domino horizontally on row 1, column 1 and row 1, column 2.
6. The “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino vertically on row 2, column 4 and row 3, column 4.
7. The “=” region at the center needs every pip to match (1 of its 6 cells is already filled) — nothing else fits. Place the 6–6 domino vertically on row 3, column 3 and row 4, column 3.
8. Row 4, column 4 has only one open neighbor, so its domino must run to row 5, column 4; the single-cell 4 region at the center needs a total of exactly 4 — nothing else fits. Place the 4–6 domino vertically on row 4, column 4 and row 5, column 4.
9. The “=” region at the left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino vertically on row 2, column 2 and row 3, column 2.
10. Row 4, column 2 has only one open neighbor, so its domino must run to row 5, column 2; the “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino vertically on row 4, column 2 and row 5, column 2.
11. Row 5, column 3 has only one open neighbor, so its domino must run to row 6, column 3; the “=” region at the center needs every pip to match (4 of its 6 cells are already filled) — nothing else fits. Place the 2–6 domino vertically on row 5, column 3 and row 6, column 3.
12. Row 6, column 2 has only one open neighbor, so its domino must run to row 7, column 2; the “=” region at the bottom-left needs every pip to match (2 of its 6 cells are already filled) — nothing else fits. Place the 2–2 domino vertically on row 6, column 2 and row 7, column 2.
13. Row 6, column 4 has only one open neighbor, so its domino must run to row 7, column 4; the “=” region at the center needs every pip to match (5 of its 6 cells are already filled) — nothing else fits. Place the 1–6 domino vertically on row 6, column 4 and row 7, column 4.
14. Row 8, column 1 has only one open neighbor, so its domino must run to row 8, column 2; the single-cell “<3” region at the bottom-left must total less than 3 — nothing else fits. Place the 0–2 domino horizontally on row 8, column 1 and row 8, column 2.
15. Row 7, column 3 has only one open neighbor, so its domino must run to row 8, column 3; the “=” region at the bottom-left needs every pip to match (5 of its 6 cells are already filled) — nothing else fits. Place the 2–5 domino vertically on row 7, column 3 and row 8, column 3.
16. Row 8, column 4 has only one open neighbor, so its domino must run to row 8, column 5; the 11 region at the bottom needs a total of exactly 11 (1 of its 3 cells is already filled) — nothing else fits. Place the 3–3 domino horizontally on row 8, column 4 and row 8, column 5.