Pips answers for Sunday, August 9, 2026

Start with the “=” region at the top-left: all 2 cells must show the same number, and only 1 or 2 or 4 or 6 appear on enough dominoes to fill it.

• the “=” region at the top-left: 1, 1
• the single-cell “>4” region at the top: 5
• the “=” region at the top-right: 6, 6
• the “=” region at the bottom-left: 4, 4
• the “=” region at the bottom: 2, 2
• the single-cell “<1” region at the bottom-right: 0

1. The “=” region at the top-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino vertically on row 1, column 4 and row 2, column 4.
2. The “=” region at the top-left needs every pip to match — nothing else fits. Place the 1–5 domino horizontally on row 1, column 2 and row 1, column 3.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino horizontally on row 3, column 1 and row 3, column 2.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–2 domino horizontally on row 3, column 3 and row 3, column 4.

Start with the 8 region at the top-left: only 2 + 6, or 3 + 5 can make it with these dominoes.

• the 8 region at the top-left: 2, 6
• the 6 region at the top-left: 2, 4
• the “=” region at the top-right: 6, 6
• the “<4” region at the top-right: 1, 1
• the single-cell “>2” region at the right: 5
• the “=” region at the bottom: 5, 5, 5
• the single-cell “>1” region at the bottom-right: 2

1. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the bottom needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 4, column 2 and row 4, column 3.
2. Row 4, column 4 has only one open neighbor, so its domino must run to row 4, column 5; the “=” region at the bottom needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 2–5 domino horizontally on row 4, column 4 and row 4, column 5.
3. The “<4” region at the top-right must total less than 4 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–5 domino vertically on row 2, column 6 and row 3, column 6.
4. The “=” region at the top-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino horizontally on row 1, column 5 and row 1, column 6.
5. The 6 region at the top-left needs a total of exactly 6 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino horizontally on row 1, column 3 and row 1, column 4.
6. The 8 region at the top-left needs a total of exactly 8 — nothing else fits. Place the 2–2 domino horizontally on row 1, column 1 and row 1, column 2.
7. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the 8 region at the top-left needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino vertically on row 2, column 1 and row 3, column 1.

Start with the 0 region at the top-left: the only way to make it with these dominoes is 0 + 0.

• the 8 region at the top-right: 2, 6
• the single-cell “>5” region at the top-right: 6
• the “=” region at the top: 4, 4
• the “=” region at the top-right: 4, 4, 4
• the 0 region at the top-left: 0, 0
• the single-cell 2 region at the top-right: 2
• the 15 region at the left: 3, 6, 6
• the 2 region at the center: 1, 1
• the single-cell 4 region at the left: 4
• the single-cell “<4” region at the left: 3
• the “=” region at the right: 5, 5
• the single-cell “>5” region at the right: 6
• the single-cell “<4” region at the bottom-left: 3
• the single-cell “>4” region at the bottom: 5
• the single-cell “>5” region at the bottom-right: 6
• the 7 region at the bottom: 1, 1, 1, 2, 2
• the single-cell “<3” region at the bottom: 2
• the single-cell “<2” region at the bottom-right: 1

1. The 0 region at the top-left needs a total of exactly 0 — nothing else fits. Place the 0–6 domino vertically on row 3, column 2 and row 4, column 2.
2. The 0 region at the top-left needs a total of exactly 0 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino vertically on row 2, column 1 and row 3, column 1.
3. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the top needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino vertically on row 2, column 4 and row 3, column 4.
4. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the 15 region at the left needs a total of exactly 15 (1 of its 3 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino vertically on row 4, column 1 and row 5, column 1.
5. The 2 region at the center needs a total of exactly 2 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–1 domino vertically on row 4, column 4 and row 5, column 4.
6. Row 4, column 3 has only one open neighbor, so its domino must run to row 5, column 3; the 15 region at the left needs a total of exactly 15 (2 of its 3 cells are already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino vertically on row 4, column 3 and row 5, column 3.
7. The 8 region at the top-right needs a total of exactly 8 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 1, column 7 and row 1, column 8.
8. The 7 region at the bottom needs a total of exactly 7 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino vertically on row 7, column 7 and row 8, column 7.
9. The “=” region at the top-right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino vertically on row 1, column 6 and row 2, column 6.
10. The “=” region at the top-right needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 2–4 domino horizontally on row 3, column 6 and row 3, column 7.
11. Row 4, column 6 has only one open neighbor, so its domino must run to row 5, column 6; the “=” region at the top-right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 4–5 domino vertically on row 4, column 6 and row 5, column 6.
12. Row 5, column 7 has only one open neighbor, so its domino must run to row 5, column 8; the “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino horizontally on row 5, column 7 and row 5, column 8.
13. Row 7, column 5 has only one open neighbor, so its domino must run to row 8, column 5; the single-cell “>4” region at the bottom must total more than 4 — nothing else fits. Place the 1–5 domino vertically on row 7, column 5 and row 8, column 5.
14. Row 8, column 6 has only one open neighbor, so its domino must run to row 9, column 6; the 7 region at the bottom needs a total of exactly 7 (2 of its 5 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino vertically on row 8, column 6 and row 9, column 6.
15. The 7 region at the bottom needs a total of exactly 7 (3 of its 5 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–2 domino vertically on row 8, column 4 and row 9, column 4.
16. Row 7, column 3 has only one open neighbor, so its domino must run to row 8, column 3; the single-cell “<4” region at the bottom-left must total less than 4 — nothing else fits. Place the 1–3 domino vertically on row 7, column 3 and row 8, column 3.