Pips answers for Friday, August 14, 2026

Start with the 6 region at the top: only 1 + 2 + 3, or 2 + 2 + 2 can make it with these dominoes.

• the 6 region at the top: 2, 2, 2
• the single-cell 6 region at the left: 6
• the 6 region at the center: 3, 3
• the single-cell 6 region at the right: 6
• the 6 region at the right: 1, 5
• the single-cell 2 region at the bottom: 2

1. The 6 region at the center needs a total of exactly 6 — nothing else fits. Place the 3–3 domino vertically on row 2, column 2 and row 3, column 2.
2. The 6 region at the top needs a total of exactly 6 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino vertically on row 1, column 1 and row 2, column 1.
3. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 6 region at the top needs a total of exactly 6 (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino horizontally on row 1, column 2 and row 1, column 3.
4. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the single-cell 6 region at the right needs a total of exactly 6 — nothing else fits. Place the 5–6 domino vertically on row 2, column 4 and row 3, column 4.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the 6 region at the right needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 3, column 3 and row 4, column 3.

Start with the “=” region at the center: all 4 cells must show the same number, and only 3s appear on enough dominoes to fill it.

• the 9 region at the top-left: 4, 5
• the “=” region at the center: 3, 3, 3, 3
• the 9 region at the left: 4, 5
• the single-cell “>0” region at the bottom-left: 6
• the 3 region at the bottom: 1, 2

1. The “=” region at the center needs every pip to match — 7 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–3 domino vertically on row 3, column 4 and row 4, column 4.
2. The 3 region at the bottom needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino vertically on row 4, column 3 and row 5, column 3.
3. Row 2, column 4 has only one open neighbor, so its domino must run to row 2, column 3; the “=” region at the center needs every pip to match (1 of its 4 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–5 domino horizontally on row 2, column 3 and row 2, column 4.
4. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the center needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino horizontally on row 3, column 2 and row 3, column 3.
5. Row 2, column 2 has only one open neighbor, so its domino must run to row 1, column 2; the 9 region at the top-left needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino vertically on row 1, column 2 and row 2, column 2.
6. Row 3, column 5 has only one open neighbor, so its domino must run to row 3, column 6; the “=” region at the center needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 3–6 domino horizontally on row 3, column 5 and row 3, column 6.
7. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the single-cell “>0” region at the bottom-left must total more than 0 — nothing else fits. Place the 5–6 domino horizontally on row 4, column 1 and row 4, column 2.

Start with the 11 region at the right: the only way to make it with these dominoes is 5 + 6.

• the “=” region at the top-left: 2, 2, 2
• the 16 region at the top-left: 5, 5, 6
• the single-cell 1 region at the top: 1
• the “<3” region at the top-right: 0, 1, 1
• the 7 region at the top: 3, 4
• the 6 region at the left: 1, 2, 3
• the 8 region at the center: 3, 5
• the 11 region at the right: 5, 6
• the 15 region at the bottom-left: 3, 6, 6
• the single-cell 3 region at the bottom: 3
• the 7 region at the bottom-right: 2, 5
• the single-cell 0 region at the bottom: 0
• the 10 region at the bottom-right: 4, 6
• the 8 region at the bottom: 4, 4

1. Row 2, column 8 has only one open neighbor, so its domino must run to row 3, column 8; the “<3” region at the top-right must total less than 3 — nothing else fits. Place the 1–1 domino vertically on row 2, column 8 and row 3, column 8.
2. Row 4, column 8 has only one open neighbor, so its domino must run to row 5, column 8; the “<3” region at the top-right must total less than 3 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–5 domino vertically on row 4, column 8 and row 5, column 8.
3. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 1, column 2 and row 1, column 3.
4. The 7 region at the top needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 2, column 5 and row 3, column 5.
5. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 1, column 1 and row 2, column 1.
6. Row 4, column 5 has only one open neighbor, so its domino must run to row 5, column 5; the 7 region at the top needs a total of exactly 7 (1 of its 2 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 4, column 5 and row 5, column 5.
7. Row 5, column 6 has only one open neighbor, so its domino must run to row 5, column 7; the 8 region at the center needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–6 domino horizontally on row 5, column 6 and row 5, column 7.
8. The 7 region at the bottom-right needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 7, column 5 and row 7, column 6.
9. Row 7, column 7 has only one open neighbor, so its domino must run to row 8, column 7; the 7 region at the bottom-right needs a total of exactly 7 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 7, column 7 and row 8, column 7.
10. The 8 region at the bottom needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino vertically on row 8, column 5 and row 9, column 5.
11. Row 9, column 6 has only one open neighbor, so its domino must run to row 9, column 7; the 8 region at the bottom needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino horizontally on row 9, column 6 and row 9, column 7.
12. The 15 region at the bottom-left needs a total of exactly 15 — nothing else fits. Place the 6–6 domino horizontally on row 7, column 2 and row 7, column 3.
13. The 16 region at the top-left needs a total of exactly 16 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 3, column 1 and row 3, column 2.
14. Row 4, column 1 has only one open neighbor, so its domino must run to row 5, column 1; the 16 region at the top-left needs a total of exactly 16 (2 of its 3 cells are already filled) — nothing else fits. Place the 1–5 domino vertically on row 4, column 1 and row 5, column 1.
15. Row 5, column 2 has only one open neighbor, so its domino must run to row 5, column 3; the 6 region at the left needs a total of exactly 6 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 5, column 2 and row 5, column 3.
16. Row 8, column 2 has only one open neighbor, so its domino must run to row 9, column 2; the 15 region at the bottom-left needs a total of exactly 15 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–3 domino vertically on row 8, column 2 and row 9, column 2.

This board has more than one valid layout; the steps follow the official answer.