Pips answers for Saturday, August 15, 2026

Start with the “=” region at the top: all 4 cells must show the same number, and only 6s appear on enough dominoes to fill it.

• the 8 region at the top-left: 0, 4, 4
• the “=” region at the top: 6, 6, 6, 6
• the “=” region at the bottom-right: 3, 3
• the single-cell 5 region at the bottom: 5

1. The single-cell 5 region at the bottom needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 2, column 3 and row 3, column 3.
2. The “=” region at the top needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 6–6 domino horizontally on row 1, column 3 and row 1, column 4.
3. The “=” region at the top needs every pip to match (3 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 1, column 2 and row 2, column 2.
4. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the 8 region at the top-left needs a total of exactly 8 (1 of its 3 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 3–3 domino vertically on row 2, column 4 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the “<3” region at the bottom: the only way to make it with these dominoes is 0 + 1 + 1.

• the “>8” region at the top: 4, 6
• the single-cell “>4” region at the top-left: 6
• the 6 region at the center: 3, 3
• the “=” region at the top-right: 2, 2
• the single-cell “>4” region at the right: 6
• the “<3” region at the bottom: 0, 1, 1
• the single-cell “<3” region at the bottom: 2

1. The “<3” region at the bottom must total less than 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 4, column 3 and row 5, column 3.
2. Row 4, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “<3” region at the bottom must total less than 3 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 3, column 4 and row 4, column 4.
3. The 6 region at the center needs a total of exactly 6 — nothing else fits. Place the 1–3 domino vertically on row 3, column 2 and row 4, column 2.
4. The 6 region at the center needs a total of exactly 6 (1 of its 2 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 2, column 1 and row 2, column 2.
5. The “>8” region at the top must total more than 8 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 1, column 1 and row 1, column 2.
6. The “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 1, column 3 and row 2, column 3.
7. Row 2, column 4 has only one open neighbor, so its domino must run to row 1, column 4; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino vertically on row 1, column 4 and row 2, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 0 region at the top-right: the only way to make it with these dominoes is 0 + 0 + 0.

• the single-cell “>4” region at the top-left: 5
• the single-cell “>0” region at the top: 2
• the “>16” region at the top-right: 5, 6, 6
• the single-cell “>3” region at the top-right: 4
• the “=” region at the top-left: 1, 1, 1, 1
• the 0 region at the top-right: 0, 0, 0
• the single-cell “<3” region at the center: 2
• the “=” region at the right: 6, 6
• the “=” region at the bottom: 4, 4, 4, 4
• the 8 region at the bottom-right: 2, 6
• the 0 region at the bottom-right: 0, 0
• the single-cell “>3” region at the bottom: 5
• the single-cell “>3” region at the bottom: 4

1. The 0 region at the top-right needs a total of exactly 0 — nothing else fits. Place the 0–0 domino horizontally on row 3, column 5 and row 3, column 6.
2. Row 4, column 5 has only one open neighbor, so its domino must run to row 5, column 5; the 0 region at the top-right needs a total of exactly 0 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 4, column 5 and row 5, column 5.
3. The 0 region at the bottom-right needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 10, column 5 and row 10, column 6.
4. The “=” region at the top-left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino vertically on row 2, column 2 and row 3, column 2.
5. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell “>0” region at the top must total more than 0 — nothing else fits. Place the 1–2 domino vertically on row 1, column 3 and row 2, column 3.
6. Row 4, column 2 has only one open neighbor, so its domino must run to row 5, column 2; the “=” region at the top-left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–1 domino vertically on row 4, column 2 and row 5, column 2.
7. Row 7, column 3 has only one open neighbor, so its domino must run to row 8, column 3; the “=” region at the bottom needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 7, column 3 and row 8, column 3.
8. Row 5, column 6 has only one open neighbor, so its domino must run to row 5, column 7; the “=” region at the right needs every pip to match — nothing else fits. Place the 6–6 domino horizontally on row 5, column 6 and row 5, column 7.
9. The “=” region at the bottom needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 9, column 3 and row 10, column 3.
10. Row 8, column 4 has only one open neighbor, so its domino must run to row 9, column 4; the “=” region at the bottom needs every pip to match (3 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 8, column 4 and row 9, column 4.
11. The “>16” region at the top-right must total more than 16 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino vertically on row 1, column 5 and row 2, column 5.
12. Row 1, column 6 has only one open neighbor, so its domino must run to row 1, column 7; the “>16” region at the top-right must total more than 16 (2 of its 3 cells are already filled) — nothing else fits. Place the 4–6 domino horizontally on row 1, column 6 and row 1, column 7.
13. Row 7, column 6 has only one open neighbor, so its domino must run to row 8, column 6; the 8 region at the bottom-right needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 7, column 6 and row 8, column 6.
14. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell “>4” region at the top-left must total more than 4 — nothing else fits. Place the 0–5 domino vertically on row 1, column 1 and row 2, column 1.
15. Row 9, column 6 has only one open neighbor, so its domino must run to row 9, column 5; the 0 region at the bottom-right needs a total of exactly 0 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino horizontally on row 9, column 5 and row 9, column 6.

This board has more than one valid layout; the steps follow the official answer.