Pips answers for Thursday, August 20, 2026

Start with the 10 region at the top-left: only 4 + 6, or 5 + 5 can make it with these dominoes.

• the single-cell “<1” region at the top-left: 0
• the 10 region at the top-left: 4, 6
• the 10 region at the top-right: 3, 3, 4
• the 10 region at the center: 5, 5

1. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell “<1” region at the top-left must total less than 1 — nothing else fits. Place the 0–4 domino horizontally on row 1, column 1 and row 1, column 2.
2. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the 10 region at the top-left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino vertically on row 2, column 2 and row 3, column 2.
3. The 10 region at the center needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–5 domino vertically on row 3, column 3 and row 4, column 3.
4. The 10 region at the top-right needs a total of exactly 10 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino horizontally on row 1, column 4 and row 1, column 5.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the 10 region at the top-right needs a total of exactly 10 (2 of its 3 cells are already filled) — nothing else fits. Place the 1–4 domino vertically on row 2, column 4 and row 3, column 4.

Start with the “=” region at the left: all 3 cells must show the same number, and only 2 or 4 appear on enough dominoes to fill it.

• the 12 region at the top-left: 4, 4, 4
• the single-cell “<2” region at the top-right: 1
• the “=” region at the left: 2, 2, 2
• the “=” region at the center: 5, 5
• the 9 region at the bottom-right: 3, 6
• the single-cell “<2” region at the bottom-left: 0
• the 5 region at the bottom: 1, 4

1. The 9 region at the bottom-right needs a total of exactly 9 — 6 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino horizontally on row 3, column 4 and row 3, column 5.
2. The “=” region at the center needs every pip to match — nothing else fits. Place the 5–6 domino horizontally on row 2, column 4 and row 2, column 5.
3. The “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino horizontally on row 2, column 2 and row 2, column 3.
4. The 12 region at the top-left needs a total of exactly 12 — nothing else fits. Place the 4–4 domino horizontally on row 1, column 1 and row 1, column 2.
5. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the 12 region at the top-left needs a total of exactly 12 (2 of its 3 cells are already filled) — nothing else fits. Place the 1–4 domino horizontally on row 1, column 3 and row 1, column 4.
6. The “=” region at the left needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 1–2 domino horizontally on row 3, column 2 and row 3, column 3.
7. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–2 domino vertically on row 2, column 1 and row 3, column 1.

Start with the 3 region at the top-left: only 0 + 3, or 1 + 2 can make it with these dominoes.

• the 3 region at the top-left: 1, 2
• the “=” region at the top: 6, 6, 6
• the single-cell “>0” region at the top-left: 1
• the “=” region at the left: 5, 5, 5
• the single-cell “>3” region at the left: 4
• the single-cell “>4” region at the center: 5
• the “=” region at the right: 4, 4, 4
• the 3 region at the right: 0, 3
• the single-cell “>4” region at the left: 6
• the 9 region at the bottom-left: 3, 3, 3
• the “>10” region at the bottom-right: 5, 6
• the “<3” region at the bottom-right: 0, 2
• the single-cell “>3” region at the bottom-right: 4

1. The “<3” region at the bottom-right must total less than 3 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–5 domino horizontally on row 6, column 6 and row 6, column 7.
2. The 3 region at the right needs a total of exactly 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino vertically on row 5, column 8 and row 6, column 8.
3. The “=” region at the right needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino horizontally on row 4, column 7 and row 4, column 8.
4. Row 4, column 6 has only one open neighbor, so its domino must run to row 5, column 6; the “=” region at the right needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 4, column 6 and row 5, column 6.
5. Row 7, column 6 has only one open neighbor, so its domino must run to row 8, column 6; the “>10” region at the bottom-right must total more than 10 (1 of its 2 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino vertically on row 7, column 6 and row 8, column 6.
6. The “=” region at the top needs every pip to match — 6 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino vertically on row 1, column 4 and row 2, column 4.
7. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 5–6 domino vertically on row 3, column 4 and row 4, column 4.
8. The 9 region at the bottom-left needs a total of exactly 9 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino vertically on row 5, column 1 and row 6, column 1.
9. Row 7, column 1 has only one open neighbor, so its domino must run to row 8, column 1; the 9 region at the bottom-left needs a total of exactly 9 (1 of its 3 cells is already filled) — nothing else fits. Place the 3–3 domino vertically on row 7, column 1 and row 8, column 1.
10. The “=” region at the left needs every pip to match — nothing else fits. Place the 5–5 domino vertically on row 3, column 1 and row 4, column 1.
11. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 4–5 domino horizontally on row 4, column 2 and row 4, column 3.
12. The 3 region at the top-left needs a total of exactly 3 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino vertically on row 1, column 1 and row 2, column 1.
13. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 3 region at the top-left needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino horizontally on row 1, column 2 and row 1, column 3.