Pips answers for Friday, August 21, 2026

Start with the “=” region at the bottom: all 3 cells must show the same number, and only 5s appear on enough dominoes to fill it.

• the single-cell “<1” region at the center: 0
• the single-cell “>4” region at the right: 6
• the “=” region at the bottom: 5, 5, 5
• the “=” region at the bottom-right: 3, 3
• the single-cell “>1” region at the bottom-left: 2

1. The single-cell “<1” region at the center must total less than 1 — nothing else fits. Place the 0–4 domino vertically on row 1, column 3 and row 2, column 3.
2. The “=” region at the bottom-right needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino vertically on row 2, column 4 and row 3, column 4.
3. The “=” region at the bottom needs every pip to match — nothing else fits. Place the 3–5 domino horizontally on row 4, column 3 and row 4, column 4.
4. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the single-cell “>1” region at the bottom-left must total more than 1 — nothing else fits. Place the 2–5 domino horizontally on row 4, column 1 and row 4, column 2.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the bottom needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–5 domino horizontally on row 3, column 2 and row 3, column 3.

Start with the “=” region at the right: all 3 cells must show the same number, and only 4 or 6 appear on enough dominoes to fill it.

• the single-cell “>3” region at the top-right: 4
• the 8 region at the left: 1, 2, 5
• the “=” region at the center: 4, 4
• the “=” region at the right: 6, 6, 6
• the single-cell “<4” region at the right: 3
• the “<3” region at the bottom-right: 0, 0, 1

1. The “=” region at the right needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino vertically on row 2, column 5 and row 3, column 5.
2. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the single-cell “>3” region at the top-right must total more than 3 — nothing else fits. Place the 4–6 domino vertically on row 1, column 4 and row 2, column 4.
3. The “<3” region at the bottom-right must total less than 3 — nothing else fits. Place the 0–0 domino horizontally on row 4, column 4 and row 4, column 5.
4. The 8 region at the left needs a total of exactly 8 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino horizontally on row 4, column 2 and row 4, column 3.
5. The “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino horizontally on row 3, column 3 and row 3, column 4.
6. The 8 region at the left needs a total of exactly 8 (1 of its 3 cells is already filled) — nothing else fits. Place the 1–4 domino horizontally on row 2, column 2 and row 2, column 3.
7. Row 3, column 2 has only one open neighbor, so its domino must run to row 3, column 1; the 8 region at the left needs a total of exactly 8 (2 of its 3 cells are already filled) — nothing else fits. Place the 5–5 domino horizontally on row 3, column 1 and row 3, column 2.

Start with the “>10” region at the bottom: only 5 + 6, or 6 + 6 can make it with these dominoes.

• the “=” region at the top-right: 3, 3
• the single-cell “>3” region at the top-right: 5
• the “=” region at the top-left: 2, 2
• the single-cell “<3” region at the top: 2
• the “=” region at the top-left: 1, 1
• the single-cell 5 region at the top: 5
• the “=” region at the right: 4, 4, 4, 4
• the single-cell “<3” region at the top-right: 2
• the single-cell “>3” region at the left: 6
• the single-cell 3 region at the right: 3
• the “≠” region at the bottom-left: 0, 1, 2, 4, 5, 6
• the “>15” region at the right: 5, 5, 6
• the “>10” region at the bottom: 6, 6
• the “=” region at the bottom-right: 3, 3, 3, 3
• the single-cell “<2” region at the bottom: 1

1. The “>10” region at the bottom must total more than 10 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino vertically on row 8, column 5 and row 9, column 5.
2. Row 7, column 5 has only one open neighbor, so its domino must run to row 7, column 6; the “>15” region at the right must total more than 15 — nothing else fits. Place the 5–5 domino horizontally on row 7, column 5 and row 7, column 6.
3. The “=” region at the right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 4, column 5 and row 5, column 5.
4. Row 5, column 6 has only one open neighbor, so its domino must run to row 5, column 7; the “=” region at the right needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 3–4 domino horizontally on row 5, column 6 and row 5, column 7.
5. The “=” region at the right needs every pip to match (3 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 3, column 5 and row 3, column 6.
6. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 9, column 7 and row 10, column 7.
7. Row 7, column 7 has only one open neighbor, so its domino must run to row 8, column 7; the “>15” region at the right must total more than 15 (2 of its 3 cells are already filled) — nothing else fits. Place the 3–6 domino vertically on row 7, column 7 and row 8, column 7.
8. Row 10, column 5 has only one open neighbor, so its domino must run to row 10, column 6; the single-cell “<2” region at the bottom must total less than 2 — nothing else fits. Place the 1–3 domino horizontally on row 10, column 5 and row 10, column 6.
9. The “=” region at the top-left needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 2, column 2 and row 2, column 3.
10. The “=” region at the top-left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 3, column 2 and row 3, column 3.
11. Row 4, column 2 has only one open neighbor, so its domino must run to row 5, column 2; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 4, column 2 and row 5, column 2.
12. The “=” region at the top-right needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 1, column 5 and row 2, column 5.
13. Row 1, column 6 has only one open neighbor, so its domino must run to row 1, column 7; the “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino horizontally on row 1, column 6 and row 1, column 7.
14. The “≠” region at the bottom-left needs every pip to be different — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 7, column 2 and row 7, column 3.
15. Row 8, column 2 has only one open neighbor, so its domino must run to row 9, column 2; the “≠” region at the bottom-left needs every pip to be different (2 of its 6 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 8, column 2 and row 9, column 2.
16. Row 10, column 1 has only one open neighbor, so its domino must run to row 10, column 2; the “≠” region at the bottom-left needs every pip to be different (4 of its 6 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 10, column 1 and row 10, column 2.

This board has more than one valid layout; the steps follow the official answer.