Pips answers for Saturday, August 22, 2026

Start with the “=” region at the top-left: all 2 cells must show the same number, and only 0 or 2 or 6 appear on enough dominoes to fill it.

• the single-cell “<3” region at the top-left: 2
• the “=” region at the top-left: 6, 6
• the “=” region at the top-right: 2, 2
• the “=” region at the center: 0, 0
• the “>6” region at the right: 3, 5

1. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the “=” region at the top-right needs every pip to match — nothing else fits. Place the 2–2 domino horizontally on row 1, column 4 and row 1, column 5.
2. The “=” region at the top-left needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 1, column 1 and row 1, column 2.
3. Row 2, column 2 has only one open neighbor, so its domino must run to row 3, column 2; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 2, column 2 and row 3, column 2.
4. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino horizontally on row 3, column 3 and row 3, column 4.
5. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the “>6” region at the right must total more than 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino vertically on row 3, column 5 and row 4, column 5.

Start with the “<2” region at the right: only 0 + 0 + 0, or 0 + 0 + 1 can make it with these dominoes.

• the single-cell “<4” region at the top-left: 2
• the “=” region at the top: 4, 4, 4
• the single-cell “>3” region at the top-right: 6
• the “=” region at the left: 1, 1, 1
• the “<2” region at the right: 0, 0, 0
• the single-cell “<4” region at the bottom: 3
• the single-cell “>3” region at the bottom: 4

1. The “<2” region at the right must total less than 2 — 5 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–6 domino vertically on row 1, column 6 and row 2, column 6.
2. The single-cell “>3” region at the bottom must total more than 3 — 5 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino horizontally on row 3, column 3 and row 3, column 4.
3. The “=” region at the top needs every pip to match — 6 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino vertically on row 1, column 5 and row 2, column 5.
4. The “=” region at the top needs every pip to match (1 of its 3 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino horizontally on row 1, column 3 and row 1, column 4.
5. The “=” region at the left needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–1 domino horizontally on row 2, column 3 and row 2, column 4.
6. The “=” region at the left needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 1, column 2 and row 2, column 2.
7. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–4 domino vertically on row 1, column 1 and row 2, column 1.

Start with the 12 region at the right: the only way to make it with these dominoes is 6 + 6.

• the “=” region at the top-left: 5, 5
• the 5 region at the top-left: 1, 4
• the 16 region at the top: 4, 6, 6
• the 2 region at the left: 0, 2
• the 5 region at the top-right: 2, 3
• the 12 region at the right: 6, 6
• the 2 region at the center: 0, 1, 1
• the 10 region at the right: 4, 6
• the “=” region at the left: 4, 4, 4
• the 8 region at the right: 3, 5
• the 1 region at the bottom-right: 0, 1
• the “=” region at the bottom-left: 2, 2
• the 4 region at the bottom-right: 0, 4

1. The 2 region at the center needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino vertically on row 4, column 4 and row 5, column 4.
2. The 16 region at the top needs a total of exactly 16 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 2, column 4 and row 3, column 4.
3. The “=” region at the left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino horizontally on row 6, column 1 and row 6, column 2.
4. The “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 2–2 domino vertically on row 7, column 3 and row 8, column 3.
5. Row 5, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 4, column 1 and row 5, column 1.
6. The 12 region at the right needs a total of exactly 12 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino vertically on row 4, column 8 and row 5, column 8.
7. The 1 region at the bottom-right needs a total of exactly 1 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 6, column 7 and row 6, column 8.
8. Row 7, column 8 has only one open neighbor, so its domino must run to row 8, column 8; the 4 region at the bottom-right needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino vertically on row 7, column 8 and row 8, column 8.
9. The 10 region at the right needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 5, column 6 and row 6, column 6.
10. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 3; the 16 region at the top needs a total of exactly 16 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 1, column 3 and row 1, column 4.
11. The 5 region at the top-right needs a total of exactly 5 — nothing else fits. Place the 2–6 domino horizontally on row 3, column 7 and row 3, column 8.
12. Row 3, column 6 has only one open neighbor, so its domino must run to row 4, column 6; the 5 region at the top-right needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 3, column 6 and row 4, column 6.
13. The “=” region at the top-left needs every pip to match — nothing else fits. Place the 4–5 domino horizontally on row 1, column 1 and row 1, column 2.
14. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 2, column 1 and row 3, column 1.
15. Row 6, column 4 has only one open neighbor, so its domino must run to row 6, column 3; the 2 region at the center needs a total of exactly 2 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–3 domino horizontally on row 6, column 3 and row 6, column 4.

This board has more than one valid layout; the steps follow the official answer.