Pips answers for Monday, August 24, 2026

Start with the 1 region at the bottom-left: the only way to make it with these dominoes is 0 + 1.

• the 1 region at the bottom-left: 0, 1
• the 12 region at the bottom-left: 6, 6
• the “=” region at the bottom: 2, 2, 2
• the 12 region at the right: 6, 6

1. The 12 region at the right needs a total of exactly 12 — nothing else fits. Place the 6–6 domino horizontally on row 2, column 4 and row 2, column 5.
2. The 1 region at the bottom-left needs a total of exactly 1 — nothing else fits. Place the 1–6 domino horizontally on row 3, column 1 and row 3, column 2.
3. The 1 region at the bottom-left needs a total of exactly 1 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 3; the 12 region at the bottom-left needs a total of exactly 12 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–6 domino horizontally on row 2, column 2 and row 2, column 3.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the bottom needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 2–2 domino horizontally on row 3, column 3 and row 3, column 4.

Start with the 4 region at the center: only 1 + 3, or 2 + 2 can make it with these dominoes.

• the “=” region at the top-left: 4, 4, 4
• the “=” region at the top: 3, 3, 3
• the single-cell “<4” region at the left: 3
• the 4 region at the center: 2, 2
• the single-cell “<2” region at the right: 1
• the 8 region at the bottom: 2, 6
• the “=” region at the right: 5, 5
• the 7 region at the bottom-right: 3, 4

1. The single-cell “<2” region at the right must total less than 2 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–5 domino vertically on row 2, column 6 and row 3, column 6.
2. Row 3, column 7 has only one open neighbor, so its domino must run to row 4, column 7; the “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 3–5 domino vertically on row 3, column 7 and row 4, column 7.
3. The “=” region at the top-left needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino horizontally on row 1, column 2 and row 1, column 3.
4. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell “<4” region at the left must total less than 4 — nothing else fits. Place the 3–4 domino horizontally on row 2, column 1 and row 2, column 2.
5. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 4; the 4 region at the center needs a total of exactly 4 — nothing else fits. Place the 2–2 domino horizontally on row 2, column 3 and row 2, column 4.
6. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the “=” region at the top needs every pip to match — nothing else fits. Place the 3–3 domino horizontally on row 1, column 4 and row 1, column 5.
7. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 2–3 domino vertically on row 2, column 5 and row 3, column 5.
8. Row 4, column 5 has only one open neighbor, so its domino must run to row 4, column 6; the 8 region at the bottom needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino horizontally on row 4, column 5 and row 4, column 6.

Start with the 1 region at the top-left: the only way to make it with these dominoes is 0 + 1.

• the 10 region at the top-left: 5, 5
• the “=” region at the top: 4, 4
• the “=” region at the top-right: 3, 3, 3, 3
• the 1 region at the top-left: 0, 1
• the 2 region at the top: 0, 2
• the “>8” region at the bottom-left: 6, 6
• the 10 region at the right: 4, 6
• the 2 region at the bottom-right: 1, 1
• the “=” region at the bottom-right: 0, 0
• the single-cell 2 region at the bottom-left: 2
• the “=” region at the bottom: 5, 5

1. The single-cell 2 region at the bottom-left needs a total of exactly 2 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino vertically on row 5, column 1 and row 6, column 1.
2. Row 6, column 2 has only one open neighbor, so its domino must run to row 6, column 3; the “=” region at the bottom needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 6, column 2 and row 6, column 3.
3. The 10 region at the top-left needs a total of exactly 10 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–5 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the 10 region at the top-left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino horizontally on row 1, column 2 and row 1, column 3.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the 1 region at the top-left needs a total of exactly 1 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino vertically on row 3, column 1 and row 4, column 1.
6. The “=” region at the top-right needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino horizontally on row 1, column 4 and row 1, column 5.
7. The 2 region at the top needs a total of exactly 2 — nothing else fits. Place the 0–3 domino horizontally on row 2, column 3 and row 2, column 4.
8. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the “=” region at the top-right needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 3–3 domino vertically on row 2, column 5 and row 3, column 5.
9. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the 2 region at the top needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–2 domino horizontally on row 3, column 3 and row 3, column 4.
10. The 10 region at the right needs a total of exactly 10 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–4 domino vertically on row 4, column 4 and row 5, column 4.
11. Row 4, column 5 has only one open neighbor, so its domino must run to row 5, column 5; the 10 region at the right needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 4, column 5 and row 5, column 5.
12. Row 6, column 4 has only one open neighbor, so its domino must run to row 6, column 5; the 2 region at the bottom-right needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino horizontally on row 6, column 4 and row 6, column 5.