Pips answers for Tuesday, August 25, 2026

Start with the 9 region at the top-left: only 3 + 6, or 4 + 5 can make it with these dominoes.

• the 9 region at the top-left: 4, 5
• the 9 region at the top-right: 0, 3, 6
• the single-cell “<2” region at the top-right: 1
• the single-cell “<2” region at the bottom-left: 1
• the 9 region at the bottom: 3, 6

1. The single-cell “<2” region at the bottom-left must total less than 2 — nothing else fits. Place the 1–6 domino horizontally on row 2, column 2 and row 2, column 3.
2. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 9 region at the top-left needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 1, column 1 and row 1, column 2.
3. The 9 region at the top-right needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 1, column 4 and row 2, column 4.
4. The 9 region at the top-right needs a total of exactly 9 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 1, column 5 and row 1, column 6.
5. Row 2, column 5 has only one open neighbor, so its domino must run to row 2, column 6; the 9 region at the top-right needs a total of exactly 9 (2 of its 3 cells are already filled) — nothing else fits. Place the 5–6 domino horizontally on row 2, column 5 and row 2, column 6.

This board has more than one valid layout; the steps follow the official answer.

Start with the 5 region at the right: only 0 + 0 + 5, or 0 + 1 + 4, or 0 + 2 + 3 can make it with these dominoes.

• the single-cell “>2” region at the top: 4
• the “=” region at the top: 6, 6
• the 5 region at the right: 0, 0, 5
• the “=” region at the center: 3, 3
• the “=” region at the right: 6, 6
• the single-cell “<2” region at the bottom-left: 1
• the “=” region at the bottom-left: 6, 6

1. The “=” region at the bottom-left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–6 domino horizontally on row 4, column 1 and row 4, column 2.
2. Row 1, column 6 has only one open neighbor, so its domino must run to row 2, column 6; the 5 region at the right needs a total of exactly 5 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino vertically on row 1, column 6 and row 2, column 6.
3. The “=” region at the right needs every pip to match — nothing else fits. Place the 5–6 domino horizontally on row 3, column 5 and row 3, column 6.
4. The “=” region at the center needs every pip to match — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino vertically on row 3, column 3 and row 4, column 3.
5. The “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–3 domino horizontally on row 2, column 2 and row 2, column 3.
6. The “=” region at the top needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino vertically on row 2, column 4 and row 3, column 4.
7. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the single-cell “>2” region at the top must total more than 2 — nothing else fits. Place the 4–6 domino horizontally on row 1, column 3 and row 1, column 4.

Start with the 2 region at the top-left: only 0 + 2, or 1 + 1 can make it with these dominoes.

• the 2 region at the top-left: 0, 2
• the 9 region at the top-left: 3, 6
• the 6 region at the left: 0, 6
• the 4 region at the left: 0, 4
• the 10 region at the center: 5, 5
• the “≠” region at the bottom-right: 0, 1, 2, 3, 4, 5
• the 9 region at the bottom: 3, 6
• the 8 region at the bottom-left: 1, 1, 6

1. The 9 region at the bottom needs a total of exactly 9 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 5, column 4 and row 6, column 4.
2. The 4 region at the left needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino horizontally on row 4, column 3 and row 4, column 4.
3. The 6 region at the left needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 4, column 1 and row 4, column 2.
4. The 2 region at the top-left needs a total of exactly 2 — nothing else fits. Place the 0–2 domino vertically on row 2, column 1 and row 3, column 1.
5. The 8 region at the bottom-left needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 7, column 3 and row 7, column 4.
6. Row 7, column 1 has only one open neighbor, so its domino must run to row 7, column 2; the 8 region at the bottom-left needs a total of exactly 8 (1 of its 3 cells is already filled) — nothing else fits. Place the 1–1 domino horizontally on row 7, column 1 and row 7, column 2.
7. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 2 region at the top-left needs a total of exactly 2 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino horizontally on row 1, column 1 and row 1, column 2.
8. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the 9 region at the top-left needs a total of exactly 9 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 1, column 3 and row 1, column 4.
9. The “≠” region at the bottom-right needs every pip to be different — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 4, column 7 and row 4, column 8.
10. Row 5, column 7 has only one open neighbor, so its domino must run to row 6, column 7; the “≠” region at the bottom-right needs every pip to be different (2 of its 6 cells are already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 5, column 7 and row 6, column 7.
11. Row 7, column 6 has only one open neighbor, so its domino must run to row 7, column 7; the “≠” region at the bottom-right needs every pip to be different (4 of its 6 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 7, column 6 and row 7, column 7.

This board has more than one valid layout; the steps follow the official answer.