Pips answers for Saturday, September 12, 2026

Start with the 10 region at the bottom: the only way to make it with these dominoes is 4 + 6.

• the single-cell “<4” region at the top-left: 3
• the single-cell “<1” region at the top: 0
• the “≠” region at the right: 2, 4, 5, 6
• the “=” region at the left: 1, 1
• the 10 region at the bottom: 4, 6

1. The single-cell “<1” region at the top must total less than 1 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino horizontally on row 1, column 2 and row 1, column 3.
2. The “≠” region at the right needs every pip to be different (1 of its 4 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 3, column 3 and row 3, column 4.
3. The “=” region at the left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 2, column 2 and row 3, column 2.
4. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell “<4” region at the top-left must total less than 4 — nothing else fits. Place the 1–3 domino vertically on row 1, column 1 and row 2, column 1.
5. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “≠” region at the right needs every pip to be different (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 1, column 4 and row 2, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 4 region at the top: only 0 + 1 + 3, or 1 + 1 + 2 can make it with these dominoes.

• the “=” region at the top-left: 0, 0
• the 4 region at the top: 1, 1, 2
• the “=” region at the left: 0, 0
• the “=” region at the center: 3, 3, 3
• the “=” region at the bottom-right: 6, 6
• the single-cell 3 region at the right: 3
• the single-cell “<2” region at the bottom: 0

1. The “=” region at the bottom-right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 3, column 4 and row 3, column 5.
2. The single-cell “<2” region at the bottom must total less than 2 — nothing else fits. Place the 0–6 domino horizontally on row 4, column 3 and row 4, column 4.
3. The “=” region at the center needs every pip to match — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 3, column 2 and row 3, column 3.
4. The “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 2, column 2 and row 2, column 3.
5. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 1, column 1 and row 2, column 1.
6. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 3; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–2 domino horizontally on row 1, column 2 and row 1, column 3.
7. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the 4 region at the top needs a total of exactly 4 (1 of its 3 cells is already filled) — nothing else fits. Place the 1–1 domino vertically on row 1, column 4 and row 2, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the “>10” region at the bottom: only 5 + 6, or 6 + 6 can make it with these dominoes.

• the single-cell “>3” region at the top-left: 4
• the single-cell “>4” region at the top-left: 6
• the single-cell 4 region at the top-right: 4
• the “=” region at the top-left: 1, 1, 1, 1, 1
• the 6 region at the top: 2, 4
• the “=” region at the top-right: 3, 3
• the single-cell “>1” region at the left: 3
• the single-cell “<4” region at the right: 2
• the single-cell “>4” region at the right: 5
• the single-cell “<2” region at the right: 0
• the single-cell 2 region at the right: 2
• the single-cell “>3” region at the bottom-left: 4
• the “=” region at the bottom-left: 3, 3
• the “>9” region at the bottom: 4, 6
• the 12 region at the bottom-right: 3, 3, 6
• the 15 region at the bottom-right: 3, 6, 6
• the single-cell “>4” region at the bottom-left: 5
• the “>10” region at the bottom: 5, 6

1. The “=” region at the top-left needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 3, column 1 and row 3, column 2.
2. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell “>4” region at the top-left must total more than 4 — nothing else fits. Place the 1–6 domino vertically on row 1, column 3 and row 2, column 3.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the single-cell “>3” region at the top-left must total more than 3 — nothing else fits. Place the 1–4 domino vertically on row 1, column 1 and row 2, column 1.
4. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the top-left needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 1–3 domino vertically on row 3, column 3 and row 4, column 3.
5. The 12 region at the bottom-right needs a total of exactly 12 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 7, column 7 and row 8, column 7.
6. Row 9, column 7 has only one open neighbor, so its domino must run to row 10, column 7; the 12 region at the bottom-right needs a total of exactly 12 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino vertically on row 9, column 7 and row 10, column 7.
7. Row 3, column 8 has only one open neighbor, so its domino must run to row 3, column 9; the “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 3, column 8 and row 3, column 9.
8. Row 3, column 5 has only one open neighbor, so its domino must run to row 3, column 6; the 6 region at the top needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 3, column 5 and row 3, column 6.
9. The 15 region at the bottom-right needs a total of exactly 15 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 7, column 9 and row 8, column 9.
10. Row 9, column 9 has only one open neighbor, so its domino must run to row 10, column 9; the 15 region at the bottom-right needs a total of exactly 15 (1 of its 3 cells is already filled) — nothing else fits. Place the 6–6 domino vertically on row 9, column 9 and row 10, column 9.
11. Row 10, column 4 has only one open neighbor, so its domino must run to row 10, column 5; the “>10” region at the bottom must total more than 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–6 domino horizontally on row 10, column 4 and row 10, column 5.
12. Row 8, column 4 has only one open neighbor, so its domino must run to row 8, column 5; the “>9” region at the bottom must total more than 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 8, column 4 and row 8, column 5.
13. The “=” region at the bottom-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 9, column 2 and row 10, column 2.
14. Row 4, column 7 has only one open neighbor, so its domino must run to row 5, column 7; the single-cell “<4” region at the right must total less than 4 — nothing else fits. Place the 2–5 domino vertically on row 4, column 7 and row 5, column 7.
15. Row 8, column 1 has only one open neighbor, so its domino must run to row 8, column 2; the single-cell “>3” region at the bottom-left must total more than 3 — nothing else fits. Place the 3–4 domino horizontally on row 8, column 1 and row 8, column 2.
16. Row 1, column 7 has only one open neighbor, so its domino must run to row 2, column 7; the single-cell 4 region at the top-right needs a total of exactly 4 — nothing else fits. Place the 0–4 domino vertically on row 1, column 7 and row 2, column 7.

This board has more than one valid layout; the steps follow the official answer.