Pips answers for Sunday, September 13, 2026

Start with the 8 region at the top-right: only 3 + 5, or 4 + 4 can make it with these dominoes.

• the 8 region at the top-right: 3, 5
• the single-cell 3 region at the top-right: 3
• the 2 region at the center: 0, 2
• the 8 region at the center: 4, 4
• the “=” region at the bottom-left: 1, 1
• the single-cell 3 region at the bottom-left: 3

1. The 8 region at the top-right needs a total of exactly 8 — nothing else fits. Place the 3–3 domino horizontally on row 1, column 5 and row 1, column 6.
2. The 2 region at the center needs a total of exactly 2 — nothing else fits. Place the 0–5 domino horizontally on row 2, column 4 and row 2, column 5.
3. The 8 region at the center needs a total of exactly 8 — nothing else fits. Place the 2–4 domino horizontally on row 3, column 3 and row 3, column 4.
4. The “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 1–4 domino horizontally on row 4, column 2 and row 4, column 3.
5. Row 5, column 1 has only one open neighbor, so its domino must run to row 5, column 2; the single-cell 3 region at the bottom-left needs a total of exactly 3 — nothing else fits. Place the 1–3 domino horizontally on row 5, column 1 and row 5, column 2.

Start with the “=” region at the center: all 3 cells must show the same number, and only 5 or 6 appear on enough dominoes to fill it.

• the single-cell “>2” region at the top-right: 3
• the single-cell “<4” region at the center: 3
• the “=” region at the center: 5, 5, 5
• the single-cell “<4” region at the left: 2
• the “>10” region at the bottom-left: 6, 6
• the 10 region at the bottom: 4, 6
• the 10 region at the bottom-right: 4, 6

1. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “<4” region at the left must total less than 4 — nothing else fits. Place the 2–6 domino horizontally on row 3, column 1 and row 3, column 2.
2. The single-cell “<4” region at the center must total less than 4 — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino vertically on row 2, column 3 and row 3, column 3.
3. The “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino vertically on row 2, column 4 and row 3, column 4.
4. The “=” region at the center needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 5–6 domino horizontally on row 4, column 4 and row 4, column 5.
5. The 10 region at the bottom-right needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–6 domino horizontally on row 3, column 5 and row 3, column 6.
6. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “>10” region at the bottom-left must total more than 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 6–6 domino horizontally on row 4, column 2 and row 4, column 3.
7. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the single-cell “>2” region at the top-right must total more than 2 — nothing else fits. Place the 2–3 domino vertically on row 1, column 5 and row 2, column 5.

Start with the “=” region at the center: all 6 cells must show the same number, and only 5 or 6 appear on enough dominoes to fill it.

• the 3 region at the top-left: 0, 1, 1, 1
• the “=” region at the left: 4, 4, 4
• the “=” region at the center: 0, 0, 0, 0
• the “=” region at the center: 6, 6, 6, 6, 6, 6
• the single-cell 5 region at the right: 5
• the single-cell 1 region at the right: 1
• the “=” region at the right: 3, 3
• the “=” region at the bottom: 5, 5, 5, 5
• the “=” region at the bottom-right: 4, 4
• the “=” region at the bottom-right: 5, 5
• the single-cell 3 region at the bottom-left: 3
• the single-cell 2 region at the bottom: 2

1. Row 10, column 6 has only one open neighbor, so its domino must run to row 10, column 7; the single-cell 2 region at the bottom needs a total of exactly 2 — nothing else fits. Place the 2–5 domino horizontally on row 10, column 6 and row 10, column 7.
2. The 3 region at the top-left needs a total of exactly 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–1 domino horizontally on row 1, column 2 and row 1, column 3.
3. The “=” region at the right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–3 domino vertically on row 5, column 9 and row 6, column 9.
4. The “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino horizontally on row 6, column 7 and row 6, column 8.
5. Row 10, column 3 has only one open neighbor, so its domino must run to row 10, column 4; the single-cell 3 region at the bottom-left needs a total of exactly 3 — nothing else fits. Place the 3–5 domino horizontally on row 10, column 3 and row 10, column 4.
6. The “=” region at the bottom needs every pip to match (1 of its 4 cells is already filled) — nothing else fits. Place the 5–6 domino vertically on row 6, column 4 and row 7, column 4.
7. Row 8, column 4 has only one open neighbor, so its domino must run to row 9, column 4; the “=” region at the bottom needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 5–5 domino vertically on row 8, column 4 and row 9, column 4.
8. The “=” region at the center needs every pip to match (2 of its 6 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino horizontally on row 6, column 5 and row 6, column 6.
9. The “=” region at the center needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino horizontally on row 4, column 5 and row 4, column 6.
10. The “=” region at the center needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 0–6 domino horizontally on row 5, column 4 and row 5, column 5.
11. The “=” region at the left needs every pip to match — nothing else fits. Place the 4–4 domino vertically on row 4, column 3 and row 5, column 3.
12. The 3 region at the top-left needs a total of exactly 3 (2 of its 4 cells are already filled) — nothing else fits. Place the 0–4 domino vertically on row 2, column 3 and row 3, column 3.
13. Row 2, column 2 has only one open neighbor, so its domino must run to row 2, column 1; the 3 region at the top-left needs a total of exactly 3 (3 of its 4 cells are already filled) — nothing else fits. Place the 1–6 domino horizontally on row 2, column 1 and row 2, column 2.
14. Row 5, column 6 has only one open neighbor, so its domino must run to row 5, column 7; the “=” region at the center needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–5 domino horizontally on row 5, column 6 and row 5, column 7.
15. Row 7, column 6 has only one open neighbor, so its domino must run to row 7, column 7; the “=” region at the center needs every pip to match (5 of its 6 cells are already filled) — nothing else fits. Place the 4–6 domino horizontally on row 7, column 6 and row 7, column 7.
16. Row 8, column 7 has only one open neighbor, so its domino must run to row 9, column 7; the “=” region at the bottom-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino vertically on row 8, column 7 and row 9, column 7.