Pips answers for Monday, September 14, 2026

Start with the “=” region at the top: all 5 cells must show the same number, and only 6s appear on enough dominoes to fill it.

• the “=” region at the top-left: 4, 4
• the “=” region at the top: 6, 6, 6, 6, 6
• the single-cell “>1” region at the top-right: 2

1. The “=” region at the top needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 6–6 domino horizontally on row 2, column 2 and row 2, column 3.
2. The “=” region at the top needs every pip to match (2 of its 5 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 1, column 3 and row 1, column 4.
3. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the “=” region at the top needs every pip to match (3 of its 5 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino horizontally on row 1, column 1 and row 1, column 2.
4. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the top-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 4–5 domino vertically on row 2, column 1 and row 3, column 1.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “=” region at the top needs every pip to match (4 of its 5 cells are already filled) — nothing else fits. Place the 1–6 domino vertically on row 2, column 4 and row 3, column 4.

Start with the 5 region at the top: only 1 + 4, or 2 + 3 can make it with these dominoes.

• the 6 region at the top-right: 0, 0, 6
• the 5 region at the top: 1, 4
• the 7 region at the center: 0, 3, 4
• the single-cell “<2” region at the left: 1
• the single-cell 2 region at the left: 2
• the 8 region at the bottom: 4, 4
• the single-cell 2 region at the bottom: 2

1. The single-cell 2 region at the left needs a total of exactly 2 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino vertically on row 3, column 1 and row 4, column 1.
2. The single-cell 2 region at the bottom needs a total of exactly 2 — nothing else fits. Place the 2–4 domino vertically on row 4, column 3 and row 5, column 3.
3. The 7 region at the center needs a total of exactly 7 (1 of its 3 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino horizontally on row 2, column 2 and row 2, column 3.
4. The 5 region at the top needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino vertically on row 3, column 2 and row 4, column 2.
5. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the 6 region at the top-right needs a total of exactly 6 — nothing else fits. Place the 0–0 domino vertically on row 1, column 4 and row 2, column 4.
6. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the 7 region at the center needs a total of exactly 7 (2 of its 3 cells are already filled) — nothing else fits. Place the 3–6 domino horizontally on row 3, column 3 and row 3, column 4.
7. Row 5, column 2 has only one open neighbor, so its domino must run to row 6, column 2; the 8 region at the bottom needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 5, column 2 and row 6, column 2.

Start with the 3 region at the top-right: only 0 + 3, or 1 + 2 can make it with these dominoes.

• the single-cell 3 region at the top-left: 3
• the “=” region at the top: 0, 0, 0
• the “=” region at the left: 2, 2, 2
• the 3 region at the top-right: 1, 2
• the 15 region at the top-right: 4, 5, 6
• the single-cell 1 region at the left: 1
• the “=” region at the center: 4, 4, 4
• the “=” region at the left: 3, 3
• the “=” region at the right: 0, 0
• the single-cell 5 region at the left: 5
• the single-cell 3 region at the center: 3
• the 10 region at the bottom-left: 5, 5
• the 5 region at the bottom-right: 1, 1, 3
• the single-cell 4 region at the bottom-left: 4
• the single-cell “>4” region at the bottom-right: 6
• the single-cell 4 region at the bottom-right: 4

1. The “=” region at the top needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino horizontally on row 1, column 4 and row 1, column 5.
2. The 10 region at the bottom-left needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino horizontally on row 7, column 1 and row 7, column 2.
3. Row 2, column 9 has only one open neighbor, so its domino must run to row 3, column 9; the 15 region at the top-right needs a total of exactly 15 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 2, column 9 and row 3, column 9.
4. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino vertically on row 2, column 5 and row 3, column 5.
5. Row 4, column 5 has only one open neighbor, so its domino must run to row 5, column 5; the “=” region at the center needs every pip to match (1 of its 3 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 4, column 5 and row 5, column 5.
6. The “=” region at the left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino horizontally on row 3, column 3 and row 3, column 4.
7. Row 1, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the single-cell 3 region at the top-left needs a total of exactly 3 — nothing else fits. Place the 2–3 domino vertically on row 1, column 3 and row 2, column 3.
8. Row 4, column 3 has only one open neighbor, so its domino must run to row 5, column 3; the “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 2–5 domino vertically on row 4, column 3 and row 5, column 3.
9. The 5 region at the bottom-right needs a total of exactly 5 — nothing else fits. Place the 1–4 domino vertically on row 6, column 9 and row 7, column 9.
10. The 15 region at the top-right needs a total of exactly 15 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 3, column 8 and row 4, column 8.
11. The “=” region at the left needs every pip to match — nothing else fits. Place the 3–5 domino vertically on row 5, column 1 and row 6, column 1.
12. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the single-cell 1 region at the left needs a total of exactly 1 — nothing else fits. Place the 1–3 domino vertically on row 3, column 1 and row 4, column 1.
13. Row 5, column 8 has only one open neighbor, so its domino must run to row 6, column 8; the “=” region at the right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–3 domino vertically on row 5, column 8 and row 6, column 8.
14. Row 6, column 7 has only one open neighbor, so its domino must run to row 7, column 7; the 5 region at the bottom-right needs a total of exactly 5 (2 of its 3 cells are already filled) — nothing else fits. Place the 1–6 domino vertically on row 6, column 7 and row 7, column 7.
15. Row 2, column 7 has only one open neighbor, so its domino must run to row 3, column 7; the 3 region at the top-right needs a total of exactly 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino vertically on row 2, column 7 and row 3, column 7.

This board has more than one valid layout; the steps follow the official answer.