Pips answers for Tuesday, October 6, 2026

Start with the 2 region at the top: the only way to make it with these dominoes is 0 + 0 + 2.

• the 2 region at the top: 0, 0, 2
• the 10 region at the left: 4, 6
• the 8 region at the right: 3, 5
• the single-cell “>2” region at the bottom-right: 3

1. The 2 region at the top needs a total of exactly 2 — nothing else fits. Place the 2–4 domino vertically on row 1, column 2 and row 2, column 2.
2. The 2 region at the top needs a total of exactly 2 (1 of its 3 cells is already filled) — nothing else fits. Place the 0–0 domino horizontally on row 1, column 3 and row 1, column 4.
3. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the 10 region at the left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 6–6 domino vertically on row 2, column 1 and row 3, column 1.
4. The 8 region at the right needs a total of exactly 8 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–5 domino vertically on row 3, column 4 and row 4, column 4.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 2, column 3; the 8 region at the right needs a total of exactly 8 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–3 domino vertically on row 2, column 3 and row 3, column 3.

Start with the 12 region at the bottom-left: the only way to make it with these dominoes is 6 + 6.

• the “=” region at the top: 5, 5
• the single-cell “<2” region at the top-right: 0
• the “=” region at the left: 4, 4
• the single-cell “<4” region at the right: 2
• the 12 region at the bottom-left: 6, 6
• the “=” region at the center: 1, 1
• the 10 region at the bottom-right: 5, 5
• the 5 region at the bottom: 2, 3

1. The 12 region at the bottom-left needs a total of exactly 12 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 4, column 1 and row 4, column 2.
2. The 5 region at the bottom needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–3 domino vertically on row 3, column 3 and row 4, column 3.
3. The 10 region at the bottom-right needs a total of exactly 10 — nothing else fits. Place the 5–5 domino vertically on row 3, column 4 and row 4, column 4.
4. The “=” region at the left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–4 domino horizontally on row 2, column 1 and row 2, column 2.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the 12 region at the bottom-left needs a total of exactly 12 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino horizontally on row 3, column 1 and row 3, column 2.
6. The “=” region at the top needs every pip to match — nothing else fits. Place the 0–5 domino horizontally on row 1, column 3 and row 1, column 4.
7. Row 2, column 3 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino horizontally on row 2, column 3 and row 2, column 4.

Start with the 24 region at the left: the only way to make it with these dominoes is 6 + 6 + 6 + 6.

• the 11 region at the top-left: 2, 3, 3, 3
• the single-cell “<2” region at the top: 1
• the 7 region at the top-right: 2, 5
• the 24 region at the left: 6, 6, 6, 6
• the “=” region at the left: 4, 4
• the single-cell “>2” region at the left: 3
• the single-cell 5 region at the center: 5
• the “=” region at the right: 4, 4, 4
• the single-cell 0 region at the bottom: 0
• the single-cell “>4” region at the bottom-left: 6
• the “<7” region at the bottom: 2, 4
• the “<5” region at the bottom-right: 2, 2

1. The 24 region at the left needs a total of exactly 24 — nothing else fits. Place the 6–6 domino vertically on row 4, column 3 and row 5, column 3.
2. The single-cell 0 region at the bottom needs a total of exactly 0 — nothing else fits. Place the 0–4 domino vertically on row 4, column 5 and row 5, column 5.
3. The single-cell “<2” region at the top must total less than 2 — nothing else fits. Place the 1–2 domino horizontally on row 1, column 5 and row 1, column 6.
4. The 24 region at the left needs a total of exactly 24 (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 3, column 2 and row 3, column 3.
5. The 11 region at the top-left needs a total of exactly 11 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 1, column 3 and row 2, column 3.
6. Row 5, column 6 has only one open neighbor, so its domino must run to row 5, column 7; the “<7” region at the bottom must total less than 7 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino horizontally on row 5, column 6 and row 5, column 7.
7. Row 3, column 7 has only one open neighbor, so its domino must run to row 3, column 8; the “=” region at the right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino horizontally on row 3, column 7 and row 3, column 8.
8. Row 4, column 8 has only one open neighbor, so its domino must run to row 5, column 8; the “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 2–4 domino vertically on row 4, column 8 and row 5, column 8.
9. Row 3, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the single-cell 5 region at the center needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–5 domino vertically on row 2, column 5 and row 3, column 5.
10. The “=” region at the left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 4, column 1 and row 5, column 1.
11. The 11 region at the top-left needs a total of exactly 11 (1 of its 4 cells is already filled) — nothing else fits. Place the 3–4 domino vertically on row 2, column 1 and row 3, column 1.
12. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the 11 region at the top-left needs a total of exactly 11 (2 of its 4 cells are already filled) — nothing else fits. Place the 3–3 domino horizontally on row 1, column 1 and row 1, column 2.
13. Row 1, column 7 has only one open neighbor, so its domino must run to row 1, column 8; the 7 region at the top-right needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino horizontally on row 1, column 7 and row 1, column 8.

This board has more than one valid layout; the steps follow the official answer.