Pips answers for Wednesday, October 7, 2026

Hints first, answers last — open only what you need. Puzzles edited by Ian Livengood.

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Easy Pips answer — October 7, 2026

5 dominoes · 3×5 board · by Ian Livengood

Hint 1: where to start

Start with the 1 region at the top-left: the only way to make it with these dominoes is 0 + 1.

Hint 2: the pips in each region
  • the 1 region at the top-left: 0, 1
  • the single-cell “>2” region at the top: 3
  • the 9 region at the top-right: 4, 5
  • the single-cell “>1” region at the top-right: 2
  • the 9 region at the bottom: 4, 5
Hint 3: step-by-step solution
  1. The 1 region at the top-left needs a total of exactly 1 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–3 domino horizontally on row 1, column 2 and row 1, column 3.
  2. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the 1 region at the top-left needs a total of exactly 1 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–2 domino vertically on row 1, column 1 and row 2, column 1.
  3. The 9 region at the top-right needs a total of exactly 9 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino vertically on row 2, column 4 and row 3, column 4.
  4. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 5; the 9 region at the top-right needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–5 domino horizontally on row 1, column 4 and row 1, column 5.
  5. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 2; the 9 region at the bottom needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–4 domino horizontally on row 3, column 2 and row 3, column 3.
Full answer board
1>29>19

Medium Pips answer — October 7, 2026

7 dominoes · 5×4 board · by Ian Livengood

Hint 1: where to start

Start with the “<2” region at the center: the only way to make it with these dominoes is 0 + 0 + 0 + 0 + 0 + 0 + 1.

Hint 2: the pips in each region
  • the “=” region at the top-left: 3, 3, 3
  • the single-cell “>4” region at the top: 6
  • the “<2” region at the center: 0, 0, 0, 0, 0, 0, 1
  • the single-cell 4 region at the bottom-left: 4
Hint 3: step-by-step solution
  1. The single-cell “>4” region at the top must total more than 4 — nothing else fits. Place the 0–6 domino vertically on row 2, column 3 and row 3, column 3.
  2. Row 1, column 2 has only one open neighbor, so its domino must run to row 2, column 2; the “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 1, column 2 and row 2, column 2.
  3. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the top-left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 0–3 domino vertically on row 2, column 1 and row 3, column 1.
  4. Row 5, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the single-cell 4 region at the bottom-left needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 4, column 1 and row 5, column 1.
  5. Row 3, column 2 has only one open neighbor, so its domino must run to row 4, column 2; the “<2” region at the center must total less than 2 (2 of its 7 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 3, column 2 and row 4, column 2.
  6. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “<2” region at the center must total less than 2 (4 of its 7 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 3, column 4 and row 4, column 4.
  7. Row 4, column 3 has only one open neighbor, so its domino must run to row 5, column 3; the “<2” region at the center must total less than 2 (6 of its 7 cells are already filled) — nothing else fits. Place the 0–4 domino vertically on row 4, column 3 and row 5, column 3.

This board has more than one valid layout; the steps follow the official answer.

Full answer board
=>4<24

Hard Pips answer — October 7, 2026

12 dominoes · 6×8 board · by Rodolfo Kurchan

Hint 1: where to start

Start with the 6 region at the top — it has the fewest pip combinations on the board, so the dominoes around it are the easiest to pin down.

Hint 2: the pips in each region
  • the “>10” region at the top-left: 2, 3, 6
  • the single-cell 5 region at the top: 5
  • the “>6” region at the left: 1, 2, 4
  • the 6 region at the top: 1, 5
  • the “=” region at the right: 0, 0, 0
  • the single-cell 0 region at the center: 0
  • the “≠” region at the bottom-left: 1, 3, 4
  • the 11 region at the bottom: 3, 4, 4
  • the “=” region at the bottom-right: 6, 6, 6
  • the single-cell 5 region at the bottom-left: 5
Hint 3: step-by-step solution
  1. The “=” region at the right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 3, column 8 and row 4, column 8.
  2. Row 5, column 8 has only one open neighbor, so its domino must run to row 6, column 8; the “=” region at the bottom-right needs every pip to match — nothing else fits. Place the 6–6 domino vertically on row 5, column 8 and row 6, column 8.
  3. Row 2, column 8 has only one open neighbor, so its domino must run to row 1, column 8; the “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 1, column 8 and row 2, column 8.
  4. The 6 region at the top needs a total of exactly 6 — nothing else fits. Place the 0–5 domino vertically on row 3, column 5 and row 4, column 5.
  5. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the single-cell 5 region at the top needs a total of exactly 5 — nothing else fits. Place the 1–5 domino vertically on row 1, column 5 and row 2, column 5.
  6. The “≠” region at the bottom-left needs every pip to be different — nothing else fits. Place the 3–5 domino horizontally on row 6, column 2 and row 6, column 3.
  7. The 11 region at the bottom needs a total of exactly 11 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino horizontally on row 6, column 6 and row 6, column 7.
  8. Row 5, column 5 has only one open neighbor, so its domino must run to row 6, column 5; the 11 region at the bottom needs a total of exactly 11 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 5, column 5 and row 6, column 5.
  9. The “>10” region at the top-left must total more than 10 — 6 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino horizontally on row 1, column 2 and row 1, column 3.
  10. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “>10” region at the top-left must total more than 10 (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 1, column 1 and row 2, column 1.
  11. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “>6” region at the left must total more than 6 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 3, column 1 and row 4, column 1.
  12. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the “≠” region at the bottom-left needs every pip to be different (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 5, column 1 and row 6, column 1.

This board has more than one valid layout; the steps follow the official answer.

Full answer board
>105>66=0≠11=5