Pips answers for Tuesday, October 13, 2026

Start with the 2 region at the bottom: the only way to make it with these dominoes is 1 + 1.

• the single-cell 6 region at the top: 6
• the 6 region at the top-right: 0, 6
• the single-cell 6 region at the left: 6
• the 6 region at the center: 3, 3
• the “=” region at the bottom-right: 6, 6
• the 2 region at the bottom: 1, 1

1. The 6 region at the center needs a total of exactly 6 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 3, column 2 and row 4, column 2.
2. Row 2, column 1 has only one open neighbor, so its domino must run to row 2, column 2; the single-cell 6 region at the left needs a total of exactly 6 — nothing else fits. Place the 3–6 domino horizontally on row 2, column 1 and row 2, column 2.
3. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the 2 region at the bottom needs a total of exactly 2 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–6 domino horizontally on row 4, column 3 and row 4, column 4.
4. The 6 region at the top-right needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 1, column 3 and row 1, column 4.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the 6 region at the top-right needs a total of exactly 6 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–6 domino vertically on row 2, column 4 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the “<2” region at the bottom-left: only 0 + 0 + 0, or 0 + 0 + 1 can make it with these dominoes.

• the single-cell “>3” region at the top: 5
• the single-cell 3 region at the top: 3
• the 3 region at the top-right: 1, 2
• the “>3” region at the top-right: 0, 4
• the “<2” region at the bottom-left: 0, 0, 1
• the “>8” region at the bottom: 4, 5
• the “<4” region at the bottom: 0, 3
• the single-cell 2 region at the bottom-right: 2

1. The “<2” region at the bottom-left must total less than 2 — nothing else fits. Place the 1–5 domino horizontally on row 2, column 2 and row 2, column 3.
2. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the “<2” region at the bottom-left must total less than 2 (1 of its 3 cells is already filled) — nothing else fits. Place the 0–0 domino horizontally on row 3, column 1 and row 3, column 2.
3. The “>3” region at the top-right must total more than 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 2, column 6 and row 3, column 6.
4. The “<4” region at the bottom must total less than 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 2, column 4 and row 2, column 5.
5. The 3 region at the top-right needs a total of exactly 3 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino horizontally on row 1, column 5 and row 1, column 6.
6. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “>8” region at the bottom must total more than 8 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 3, column 3 and row 3, column 4.
7. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the single-cell “>3” region at the top must total more than 3 — nothing else fits. Place the 3–5 domino horizontally on row 1, column 3 and row 1, column 4.

This board has more than one valid layout; the steps follow the official answer.

Start with the 10 region at the bottom-right: only 4 + 6, or 5 + 5 can make it with these dominoes.

• the single-cell 4 region at the top-left: 4
• the single-cell “<2” region at the top-left: 1
• the single-cell 1 region at the top: 1
• the “=” region at the top-right: 2, 2
• the “=” region at the left: 3, 3, 3
• the 7 region at the top: 2, 5
• the single-cell 4 region at the right: 4
• the “≠” region at the left: 0, 5, 6
• the single-cell “>2” region at the right: 3
• the single-cell “<3” region at the bottom-left: 2
• the 8 region at the bottom: 2, 6
• the 10 region at the bottom-right: 4, 6
• the single-cell “<5” region at the bottom-left: 4
• the 4 region at the bottom-right: 1, 3

1. Row 1, column 6 has only one open neighbor, so its domino must run to row 2, column 6; the “=” region at the top-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 1, column 6 and row 2, column 6.
2. The “=” region at the left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino vertically on row 2, column 1 and row 3, column 1.
3. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell 4 region at the top-left needs a total of exactly 4 — nothing else fits. Place the 1–4 domino horizontally on row 1, column 1 and row 1, column 2.
4. The 10 region at the bottom-right needs a total of exactly 10 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 5, column 6 and row 6, column 6.
5. Row 3, column 6 has only one open neighbor, so its domino must run to row 4, column 6; the single-cell 4 region at the right needs a total of exactly 4 — nothing else fits. Place the 3–4 domino vertically on row 3, column 6 and row 4, column 6.
6. The “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino horizontally on row 4, column 1 and row 4, column 2.
7. The 8 region at the bottom needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 5, column 4 and row 6, column 4.
8. Row 6, column 7 has only one open neighbor, so its domino must run to row 6, column 8; the 4 region at the bottom-right needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 6, column 7 and row 6, column 8.
9. The single-cell 1 region at the top needs a total of exactly 1 — nothing else fits. Place the 1–6 domino horizontally on row 1, column 3 and row 1, column 4.
10. Row 5, column 1 has only one open neighbor, so its domino must run to row 6, column 1; the single-cell “<3” region at the bottom-left must total less than 3 — nothing else fits. Place the 2–4 domino vertically on row 5, column 1 and row 6, column 1.
11. Row 4, column 3 has only one open neighbor, so its domino must run to row 4, column 4; the “≠” region at the left needs every pip to be different (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino horizontally on row 4, column 3 and row 4, column 4.
12. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the 7 region at the top needs a total of exactly 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–5 domino vertically on row 2, column 4 and row 3, column 4.

This board has more than one valid layout; the steps follow the official answer.