Pips answers for Wednesday, October 14, 2026

Start with the “=” region at the right: all 3 cells must show the same number, and only 1s appear on enough dominoes to fill it.

• the “=” region at the left: 3, 3
• the 9 region at the top-right: 4, 5
• the “=” region at the right: 1, 1, 1
• the “<6” region at the bottom: 0, 0

1. The “<6” region at the bottom must total less than 6 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–0 domino vertically on row 4, column 2 and row 5, column 2.
2. The “=” region at the right needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–1 domino vertically on row 3, column 3 and row 4, column 3.
3. The “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–5 domino vertically on row 2, column 2 and row 3, column 2.
4. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “=” region at the left needs every pip to match — nothing else fits. Place the 3–3 domino vertically on row 2, column 1 and row 3, column 1.
5. Row 2, column 3 has only one open neighbor, so its domino must run to row 1, column 3; the 9 region at the top-right needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino vertically on row 1, column 3 and row 2, column 3.

Start with the 8 region at the bottom-right — it has the fewest pip combinations on the board, so the dominoes around it are the easiest to pin down.

• the single-cell “>3” region at the top-left: 4
• the “=” region at the top: 3, 3
• the “=” region at the top-right: 0, 0
• the single-cell “<3” region at the left: 0
• the “=” region at the bottom-left: 1, 1
• the “=” region at the center: 6, 6
• the 8 region at the bottom-right: 0, 4, 4
• the single-cell “>4” region at the bottom: 5

1. The “=” region at the bottom-left needs every pip to match — 5 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino horizontally on row 3, column 2 and row 3, column 3.
2. The single-cell “<3” region at the left must total less than 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino horizontally on row 2, column 1 and row 2, column 2.
3. The “=” region at the top needs every pip to match — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 1, column 1 and row 1, column 2.
4. The “=” region at the top needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino vertically on row 1, column 3 and row 2, column 3.
5. The “=” region at the top-right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino horizontally on row 1, column 4 and row 1, column 5.
6. The “=” region at the center needs every pip to match (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 2, column 4 and row 3, column 4.
7. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the 8 region at the bottom-right needs a total of exactly 8 (1 of its 3 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 2, column 5 and row 3, column 5.

This board has more than one valid layout; the steps follow the official answer.

Start with the 14 region at the right — it has the fewest pip combinations on the board, so the dominoes around it are the easiest to pin down.

• the “≠” region at the top-left: 1, 4, 6
• the single-cell 0 region at the top-left: 0
• the single-cell 4 region at the top: 4
• the “>7” region at the top-right: 2, 6
• the “=” region at the top-left: 3, 3
• the 9 region at the top: 0, 4, 5
• the “=” region at the left: 1, 1, 1
• the single-cell 4 region at the top-right: 4
• the single-cell 3 region at the left: 3
• the 14 region at the right: 2, 6, 6
• the single-cell “<4” region at the left: 3
• the “<3” region at the center: 0, 2
• the single-cell “>4” region at the right: 5
• the single-cell 6 region at the right: 6
• the 6 region at the bottom: 1, 5

1. The single-cell 4 region at the top-right needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 3, column 8 and row 4, column 8.
2. The 14 region at the right needs a total of exactly 14 (1 of its 3 cells is already filled) — nothing else fits. Place the 6–6 domino horizontally on row 4, column 6 and row 4, column 7.
3. The single-cell “>4” region at the right must total more than 4 — nothing else fits. Place the 5–6 domino horizontally on row 6, column 6 and row 6, column 7.
4. The 9 region at the top needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–4 domino vertically on row 1, column 5 and row 2, column 5.
5. Row 1, column 8 has only one open neighbor, so its domino must run to row 2, column 8; the “>7” region at the top-right must total more than 7 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 1, column 8 and row 2, column 8.
6. The “<3” region at the center must total less than 3 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino horizontally on row 6, column 3 and row 6, column 4.
7. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the 9 region at the top needs a total of exactly 9 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 3, column 5 and row 4, column 5.
8. Row 6, column 5 has only one open neighbor, so its domino must run to row 7, column 5; the “<3” region at the center must total less than 3 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 6, column 5 and row 7, column 5.
9. The single-cell 0 region at the top-left needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–4 domino horizontally on row 1, column 2 and row 1, column 3.
10. The “=” region at the left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino vertically on row 3, column 1 and row 4, column 1.
11. Row 2, column 3 has only one open neighbor, so its domino must run to row 3, column 3; the “=” region at the top-left needs every pip to match — nothing else fits. Place the 3–3 domino vertically on row 2, column 3 and row 3, column 3.
12. Row 4, column 2 has only one open neighbor, so its domino must run to row 4, column 3; the “=” region at the left needs every pip to match (2 of its 3 cells are already filled) — nothing else fits. Place the 1–3 domino horizontally on row 4, column 2 and row 4, column 3.
13. Row 8, column 5 has only one open neighbor, so its domino must run to row 9, column 5; the 6 region at the bottom needs a total of exactly 6 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–5 domino vertically on row 8, column 5 and row 9, column 5.
14. Row 1, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “≠” region at the top-left needs every pip to be different (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino vertically on row 1, column 1 and row 2, column 1.

This board has more than one valid layout; the steps follow the official answer.