Pips answers for Saturday, October 17, 2026

Start with the “<1” region at the right: the only way to make it with these dominoes is 0 + 0 + 0.

• the “=” region at the top: 2, 2
• the “=” region at the bottom-left: 0, 0
• the “<1” region at the right: 0, 0, 0
• the single-cell “>5” region at the bottom-left: 6

1. The “<1” region at the right must total less than 1 — nothing else fits. Place the 0–0 domino horizontally on row 2, column 4 and row 2, column 5.
2. The “=” region at the top needs every pip to match — nothing else fits. Place the 2–2 domino horizontally on row 1, column 3 and row 1, column 4.
3. Row 3, column 1 has only one open neighbor, so its domino must run to row 3, column 2; the single-cell “>5” region at the bottom-left must total more than 5 — nothing else fits. Place the 0–6 domino horizontally on row 3, column 1 and row 3, column 2.
4. Row 3, column 4 has only one open neighbor, so its domino must run to row 3, column 3; the “<1” region at the right must total less than 1 (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino horizontally on row 3, column 3 and row 3, column 4.
5. Row 2, column 2 has only one open neighbor, so its domino must run to row 1, column 2; the “=” region at the bottom-left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–1 domino vertically on row 1, column 2 and row 2, column 2.

This board has more than one valid layout; the steps follow the official answer.

Start with the 8 region at the right: only 2 + 6, or 3 + 5 can make it with these dominoes.

• the “<5” region at the top: 0, 4
• the “>8” region at the top-right: 3, 6
• the single-cell 2 region at the center: 2
• the “=” region at the left: 5, 5
• the 8 region at the right: 3, 5
• the single-cell “<4” region at the bottom-left: 3
• the “=” region at the bottom: 6, 6
• the single-cell 2 region at the bottom-right: 2

1. The single-cell 2 region at the bottom-right needs a total of exactly 2 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–6 domino horizontally on row 4, column 3 and row 4, column 4.
2. The “=” region at the bottom needs every pip to match (1 of its 2 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino horizontally on row 4, column 1 and row 4, column 2.
3. The single-cell 2 region at the center needs a total of exactly 2 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–2 domino horizontally on row 2, column 2 and row 2, column 3.
4. Row 1, column 3 has only one open neighbor, so its domino must run to row 1, column 4; the “<5” region at the top must total less than 5 (1 of its 2 cells is already filled) — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–6 domino horizontally on row 1, column 3 and row 1, column 4.
5. Row 2, column 4 has only one open neighbor, so its domino must run to row 3, column 4; the “>8” region at the top-right must total more than 8 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino vertically on row 2, column 4 and row 3, column 4.
6. The “=” region at the left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 3, column 2 and row 3, column 3.
7. Row 3, column 1 has only one open neighbor, so its domino must run to row 2, column 1; the “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 0–5 domino vertically on row 2, column 1 and row 3, column 1.

Start with the 2 region at the top-right: only 0 + 2, or 1 + 1 can make it with these dominoes.

• the 8 region at the top-left: 2, 6
• the 4 region at the top-left: 1, 3
• the “≠” region at the top: 2, 3, 6
• the 2 region at the top-right: 0, 2
• the single-cell 5 region at the top-left: 5
• the single-cell 3 region at the top-left: 3
• the single-cell 0 region at the top: 0
• the single-cell 5 region at the left: 5
• the single-cell “>1” region at the left: 2
• the 5 region at the center: 1, 4
• the single-cell 0 region at the left: 0
• the single-cell 5 region at the left: 5
• the “=” region at the right: 6, 6, 6
• the 10 region at the bottom-right: 3, 3, 4
• the “=” region at the bottom-right: 0, 0

1. The 2 region at the top-right needs a total of exactly 2 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino horizontally on row 1, column 6 and row 1, column 7.
2. The “≠” region at the top needs every pip to be different — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino horizontally on row 3, column 5 and row 3, column 6.
3. The “=” region at the right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 6–6 domino horizontally on row 5, column 8 and row 5, column 9.
4. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 8, column 7 and row 9, column 7.
5. The single-cell 0 region at the left needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–5 domino vertically on row 4, column 1 and row 5, column 1.
6. The 4 region at the top-left needs a total of exactly 4 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 1, column 3 and row 2, column 3.
7. The single-cell 5 region at the left needs a total of exactly 5 — nothing else fits. Place the 5–6 domino horizontally on row 5, column 2 and row 5, column 3.
8. The 8 region at the top-left needs a total of exactly 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 1, column 1 and row 1, column 2.
9. Row 5, column 7 has only one open neighbor, so its domino must run to row 6, column 7; the “=” region at the right needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino vertically on row 5, column 7 and row 6, column 7.
10. Row 7, column 7 has only one open neighbor, so its domino must run to row 7, column 8; the 10 region at the bottom-right needs a total of exactly 10 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino horizontally on row 7, column 7 and row 7, column 8.
11. Row 3, column 3 has only one open neighbor, so its domino must run to row 4, column 3; the single-cell 3 region at the top-left needs a total of exactly 3 — nothing else fits. Place the 2–3 domino vertically on row 3, column 3 and row 4, column 3.
12. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the 8 region at the top-left needs a total of exactly 8 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 2, column 1 and row 3, column 1.
13. Row 4, column 5 has only one open neighbor, so its domino must run to row 5, column 5; the 5 region at the center needs a total of exactly 5 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 4, column 5 and row 5, column 5.
14. Row 1, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the “≠” region at the top needs every pip to be different (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–6 domino vertically on row 1, column 5 and row 2, column 5.

This board has more than one valid layout; the steps follow the official answer.