Pips answers for Friday, October 16, 2026

Start with the “=” region at the bottom-left: all 4 cells must show the same number, and only 4s appear on enough dominoes to fill it.

• the 5 region at the top-right: 2, 3
• the “=” region at the center: 5, 5
• the “=” region at the bottom-left: 4, 4, 4, 4
• the single-cell “>1” region at the bottom: 6

1. The “=” region at the bottom-left needs every pip to match — nothing else fits. Place the 4–4 domino vertically on row 4, column 1 and row 5, column 1.
2. The “=” region at the bottom-left needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino vertically on row 3, column 2 and row 4, column 2.
3. The 5 region at the top-right needs a total of exactly 5 — nothing else fits. Place the 3–5 domino vertically on row 2, column 3 and row 3, column 3.
4. Row 2, column 4 has only one open neighbor, so its domino must run to row 1, column 4; the 5 region at the top-right needs a total of exactly 5 (1 of its 2 cells is already filled) — nothing else fits. Place the 1–2 domino vertically on row 1, column 4 and row 2, column 4.
5. Row 5, column 2 has only one open neighbor, so its domino must run to row 5, column 3; the “=” region at the bottom-left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 4–6 domino horizontally on row 5, column 2 and row 5, column 3.

Start with the 1 region at the bottom-left: the only way to make it with these dominoes is 0 + 1.

• the single-cell “<1” region at the top-right: 0
• the 3 region at the center: 1, 2
• the single-cell “>2” region at the right: 4
• the 1 region at the bottom-left: 0, 1
• the “>9” region at the center: 5, 5
• the “>9” region at the right: 5, 5
• the single-cell “>3” region at the bottom-left: 4
• the single-cell “<1” region at the bottom-right: 0

1. The 3 region at the center needs a total of exactly 3 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–1 domino vertically on row 1, column 4 and row 2, column 4.
2. The 3 region at the center needs a total of exactly 3 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 2–4 domino horizontally on row 2, column 2 and row 2, column 3.
3. The 1 region at the bottom-left needs a total of exactly 1 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 1–5 domino horizontally on row 3, column 1 and row 3, column 2.
4. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the 1 region at the bottom-left needs a total of exactly 1 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino horizontally on row 4, column 1 and row 4, column 2.
5. The single-cell “<1” region at the bottom-right must total less than 1 — nothing else fits. Place the 0–3 domino horizontally on row 4, column 4 and row 4, column 5.
6. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the “>9” region at the center must total more than 9 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 3, column 3 and row 3, column 4.
7. Row 2, column 5 has only one open neighbor, so its domino must run to row 3, column 5; the single-cell “>2” region at the right must total more than 2 — nothing else fits. Place the 4–5 domino vertically on row 2, column 5 and row 3, column 5.

Start with the 2 region at the top: only 0 + 2, or 1 + 1 can make it with these dominoes.

• the single-cell 4 region at the top-left: 4
• the “=” region at the top: 0, 0, 0
• the “>8” region at the top-right: 2, 3, 4
• the single-cell 1 region at the top-left: 1
• the single-cell 6 region at the top-left: 6
• the 2 region at the top: 1, 1
• the single-cell 5 region at the left: 5
• the “≠” region at the left: 2, 4
• the single-cell 1 region at the left: 1
• the “>9” region at the bottom: 3, 3, 4
• the “=” region at the bottom-right: 5, 5, 5, 5
• the single-cell 0 region at the bottom-left: 0
• the single-cell 2 region at the bottom-left: 2

1. The single-cell 6 region at the top-left needs a total of exactly 6 — nothing else fits. Place the 2–6 domino vertically on row 2, column 2 and row 3, column 2.
2. The single-cell 1 region at the top-left needs a total of exactly 1 — nothing else fits. Place the 1–5 domino vertically on row 2, column 1 and row 3, column 1.
3. The 2 region at the top needs a total of exactly 2 — nothing else fits. Place the 1–1 domino vertically on row 2, column 5 and row 3, column 5.
4. The “=” region at the bottom-right needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 5–5 domino vertically on row 5, column 7 and row 6, column 7.
5. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the “=” region at the top needs every pip to match — nothing else fits. Place the 0–0 domino vertically on row 1, column 4 and row 2, column 4.
6. The “=” region at the bottom-right needs every pip to match (2 of its 4 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 3, column 6 and row 4, column 6.
7. The “>8” region at the top-right must total more than 8 — nothing else fits. Place the 4–5 domino vertically on row 3, column 7 and row 4, column 7.
8. Row 3, column 4 has only one open neighbor, so its domino must run to row 4, column 4; the “=” region at the top needs every pip to match (2 of its 3 cells are already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–3 domino vertically on row 3, column 4 and row 4, column 4.
9. The single-cell 0 region at the bottom-left needs a total of exactly 0 — nothing else fits. Place the 0–1 domino vertically on row 5, column 1 and row 6, column 1.
10. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the single-cell 1 region at the left needs a total of exactly 1 — nothing else fits. Place the 1–4 domino horizontally on row 4, column 1 and row 4, column 2.
11. Row 5, column 4 has only one open neighbor, so its domino must run to row 6, column 4; the “>9” region at the bottom must total more than 9 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 5, column 4 and row 6, column 4.
12. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the single-cell 4 region at the top-left needs a total of exactly 4 — nothing else fits. Place the 2–4 domino horizontally on row 1, column 1 and row 1, column 2.
13. Row 1, column 7 has only one open neighbor, so its domino must run to row 2, column 7; the “>8” region at the top-right must total more than 8 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–3 domino vertically on row 1, column 7 and row 2, column 7.
14. Row 6, column 2 has only one open neighbor, so its domino must run to row 5, column 2; the single-cell 2 region at the bottom-left needs a total of exactly 2 — nothing else fits. Place the 1–2 domino vertically on row 5, column 2 and row 6, column 2.

This board has more than one valid layout; the steps follow the official answer.