Pips answers for Thursday, October 15, 2026

Start with the 10 region at the left: only 4 + 6, or 5 + 5 can make it with these dominoes.

• the single-cell 1 region at the top-right: 1
• the 10 region at the left: 4, 6
• the 10 region at the right: 5, 5
• the single-cell “>1” region at the left: 2
• the 10 region at the center: 4, 6
• the single-cell “>2” region at the bottom: 3

1. Row 1, column 4 has only one open neighbor, so its domino must run to row 2, column 4; the single-cell 1 region at the top-right needs a total of exactly 1 — nothing else fits. Place the 1–5 domino vertically on row 1, column 4 and row 2, column 4.
2. The 10 region at the right needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino horizontally on row 2, column 2 and row 2, column 3.
3. The 10 region at the center needs a total of exactly 10 — nothing else fits. Place the 3–6 domino vertically on row 3, column 3 and row 4, column 3.
4. The single-cell “>1” region at the left must total more than 1 — nothing else fits. Place the 2–4 domino horizontally on row 3, column 1 and row 3, column 2.
5. Row 2, column 1 has only one open neighbor, so its domino must run to row 1, column 1; the 10 region at the left needs a total of exactly 10 (1 of its 2 cells is already filled) — nothing else fits. Place the 0–4 domino vertically on row 1, column 1 and row 2, column 1.

Start with the 20 region at the bottom-right: the only way to make it with these dominoes is 5 + 5 + 5 + 5.

• the single-cell “<4” region at the top: 3
• the “=” region at the top-left: 3, 3
• the “=” region at the top-right: 4, 4
• the “=” region at the left: 4, 4
• the single-cell “<1” region at the center: 0
• the 20 region at the bottom-right: 5, 5, 5, 5
• the 6 region at the bottom-left: 2, 4
• the 3 region at the bottom: 1, 2

1. The single-cell “<1” region at the center must total less than 1 — 3 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 0–4 domino horizontally on row 3, column 2 and row 3, column 3.
2. The “=” region at the top-left needs every pip to match — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–3 domino horizontally on row 2, column 1 and row 2, column 2.
3. The “=” region at the top-right needs every pip to match — 4 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–4 domino vertically on row 1, column 3 and row 2, column 3.
4. The 20 region at the bottom-right needs a total of exactly 20 — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 4–5 domino vertically on row 2, column 4 and row 3, column 4.
5. The 20 region at the bottom-right needs a total of exactly 20 (1 of its 4 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 5–5 domino horizontally on row 4, column 3 and row 4, column 4.
6. The 3 region at the bottom needs a total of exactly 3 — nothing else fits. Place the 2–5 domino horizontally on row 5, column 3 and row 5, column 4.
7. The 6 region at the bottom-left needs a total of exactly 6 — nothing else fits. Place the 1–4 domino horizontally on row 5, column 1 and row 5, column 2.
8. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “=” region at the left needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 2–4 domino vertically on row 3, column 1 and row 4, column 1.

Start with the “>14” region at the right: only 4 + 5 + 6, or 5 + 5 + 6 can make it with these dominoes.

• the single-cell “>1” region at the top-left: 4
• the single-cell “>0” region at the top-left: 3
• the single-cell “>3” region at the top: 4
• the “>14” region at the right: 4, 5, 6
• the single-cell 5 region at the left: 5
• the “=” region at the center: 2, 2
• the 9 region at the bottom-left: 0, 3, 3, 3
• the single-cell 1 region at the left: 1
• the “>9” region at the bottom: 2, 4, 4
• the single-cell “>2” region at the right: 3
• the 4 region at the bottom-right: 0, 4

1. The single-cell 5 region at the left needs a total of exactly 5 — nothing else fits. Place the 3–5 domino vertically on row 1, column 3 and row 2, column 3.
2. The 9 region at the bottom-left needs a total of exactly 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino vertically on row 3, column 3 and row 4, column 3.
3. Row 1, column 8 has only one open neighbor, so its domino must run to row 2, column 8; the “>14” region at the right must total more than 14 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 4–6 domino vertically on row 1, column 8 and row 2, column 8.
4. The “>14” region at the right must total more than 14 (2 of its 3 cells are already filled) — nothing else fits. Place the 0–5 domino vertically on row 3, column 8 and row 4, column 8.
5. Row 4, column 7 has only one open neighbor, so its domino must run to row 3, column 7; the 4 region at the bottom-right needs a total of exactly 4 (1 of its 2 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–4 domino vertically on row 3, column 7 and row 4, column 7.
6. The “=” region at the center needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 1, column 5 and row 2, column 5.
7. The “>9” region at the bottom must total more than 9 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 2, column 6 and row 3, column 6.
8. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the “>9” region at the bottom must total more than 9 (1 of its 3 cells is already filled) — nothing else fits. Place the 4–4 domino vertically on row 3, column 5 and row 4, column 5.
9. Row 1, column 2 has only one open neighbor, so its domino must run to row 1, column 1; the single-cell “>1” region at the top-left must total more than 1 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino horizontally on row 1, column 1 and row 1, column 2.
10. The 9 region at the bottom-left needs a total of exactly 9 (1 of its 4 cells is already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 2, column 1 and row 3, column 1.
11. Row 4, column 1 has only one open neighbor, so its domino must run to row 4, column 2; the 9 region at the bottom-left needs a total of exactly 9 (2 of its 4 cells are already filled) — nothing else fits. Place the 3–3 domino horizontally on row 4, column 1 and row 4, column 2.

This board has more than one valid layout; the steps follow the official answer.