Pips answers for Monday, November 9, 2026

Start with the “<3” region at the bottom-left: the only way to make it with these dominoes is 0 + 0 + 0.

• the “<3” region at the bottom-left: 0, 0, 0
• the 9 region at the center: 3, 6
• the single-cell 4 region at the right: 4
• the 6 region at the left: 3, 3
• the single-cell “>4” region at the top-left: 6

1. The “<3” region at the bottom-left must total less than 3 — nothing else fits. Place the 0–0 domino vertically on row 3, column 2 and row 4, column 2.
2. The 6 region at the left needs a total of exactly 6 — nothing else fits. Place the 0–3 domino vertically on row 2, column 1 and row 3, column 1.
3. The 6 region at the left needs a total of exactly 6 (1 of its 2 cells is already filled) — 2 placements fit here for now, but every other one leaves some region impossible a few moves later. Place the 3–6 domino horizontally on row 2, column 2 and row 2, column 3.
4. Row 1, column 1 has only one open neighbor, so its domino must run to row 1, column 2; the single-cell “>4” region at the top-left must total more than 4 — nothing else fits. Place the 4–6 domino horizontally on row 1, column 1 and row 1, column 2.
5. Row 3, column 3 has only one open neighbor, so its domino must run to row 3, column 4; the 9 region at the center needs a total of exactly 9 (1 of its 2 cells is already filled) — nothing else fits. Place the 3–4 domino horizontally on row 3, column 3 and row 3, column 4.

Start with the “=” region at the top-left: all 4 cells must show the same number, and only 0s appear on enough dominoes to fill it.

• the “=” region at the top-left: 0, 0, 0, 0
• the single-cell “>4” region at the top: 5
• the “>10” region at the center: 3, 3, 5
• the “>4” region at the bottom-left: 2, 4
• the single-cell “<3” region at the left: 1
• the single-cell “>2” region at the center: 3
• the single-cell “>1” region at the right: 2

1. The “=” region at the top-left needs every pip to match — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–0 domino vertically on row 1, column 1 and row 2, column 1.
2. The “=” region at the top-left needs every pip to match (2 of its 4 cells are already filled) — nothing else fits. Place the 0–5 domino horizontally on row 1, column 2 and row 1, column 3.
3. The “=” region at the top-left needs every pip to match (3 of its 4 cells are already filled) — nothing else fits. Place the 0–3 domino horizontally on row 2, column 2 and row 2, column 3.
4. The single-cell “<3” region at the left must total less than 3 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 3, column 2 and row 3, column 3.
5. Row 3, column 1 has only one open neighbor, so its domino must run to row 4, column 1; the “>4” region at the bottom-left must total more than 4 — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–4 domino vertically on row 3, column 1 and row 4, column 1.
6. The “>10” region at the center must total more than 10 (1 of its 3 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–5 domino vertically on row 2, column 4 and row 3, column 4.
7. Row 3, column 5 has only one open neighbor, so its domino must run to row 2, column 5; the single-cell “>1” region at the right must total more than 1 — nothing else fits. Place the 1–2 domino vertically on row 2, column 5 and row 3, column 5.

This board has more than one valid layout; the steps follow the official answer.

Start with the 2 region at the bottom-right: only 0 + 0 + 2, or 0 + 1 + 1 can make it with these dominoes.

• the “≠” region at the top-left: 0, 2, 6
• the 7 region at the top-left: 3, 4
• the “=” region at the top-right: 1, 1, 1
• the single-cell 1 region at the top: 1
• the single-cell 5 region at the top: 5
• the “=” region at the top-right: 6, 6
• the single-cell 5 region at the center: 5
• the single-cell “<3” region at the center: 2
• the “≠” region at the right: 1, 4
• the single-cell 0 region at the right: 0
• the “<11” region at the bottom-left: 2, 2, 3, 3
• the 2 region at the bottom-right: 0, 1, 1
• the single-cell 3 region at the bottom: 3
• the single-cell 5 region at the bottom-left: 5
• the “>8” region at the bottom: 3, 6
• the single-cell 2 region at the bottom-right: 2
• the single-cell 4 region at the top-left: 4

1. The single-cell 5 region at the center needs a total of exactly 5 — nothing else fits. Place the 2–5 domino horizontally on row 3, column 3 and row 3, column 4.
2. The single-cell 2 region at the bottom-right needs a total of exactly 2 — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–2 domino horizontally on row 6, column 5 and row 6, column 6.
3. The 2 region at the bottom-right needs a total of exactly 2 (1 of its 3 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–1 domino vertically on row 4, column 6 and row 5, column 6.
4. The single-cell 0 region at the right needs a total of exactly 0 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–6 domino vertically on row 2, column 6 and row 3, column 6.
5. The “=” region at the top-right needs every pip to match (1 of its 2 cells is already filled) — nothing else fits. Place the 5–6 domino horizontally on row 2, column 4 and row 2, column 5.
6. The “>8” region at the bottom must total more than 8 — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–6 domino horizontally on row 6, column 3 and row 6, column 4.
7. The “<11” region at the bottom-left must total less than 11 — nothing else fits. Place the 3–5 domino horizontally on row 6, column 1 and row 6, column 2.
8. The “<11” region at the bottom-left must total less than 11 (1 of its 4 cells is already filled) — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 3–3 domino horizontally on row 5, column 2 and row 5, column 3.
9. The “=” region at the top-right needs every pip to match — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–1 domino horizontally on row 1, column 5 and row 1, column 6.
10. Row 1, column 4 has only one open neighbor, so its domino must run to row 1, column 3; the “=” region at the top-right needs every pip to match (2 of its 3 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–3 domino horizontally on row 1, column 3 and row 1, column 4.
11. The 7 region at the top-left needs a total of exactly 7 (1 of its 2 cells is already filled) — nothing else fits. Place the 4–4 domino horizontally on row 1, column 1 and row 1, column 2.
12. The “≠” region at the top-left needs every pip to be different — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–6 domino horizontally on row 2, column 2 and row 2, column 3.
13. The “<11” region at the bottom-left must total less than 11 (2 of its 4 cells are already filled) — 3 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 2–2 domino vertically on row 4, column 1 and row 5, column 1.
14. Row 2, column 1 has only one open neighbor, so its domino must run to row 3, column 1; the “≠” region at the top-left needs every pip to be different (1 of its 3 cells is already filled) — 4 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 0–2 domino vertically on row 2, column 1 and row 3, column 1.
15. Row 3, column 5 has only one open neighbor, so its domino must run to row 4, column 5; the “≠” region at the right needs every pip to be different — 2 placements fit here for now; this one matches the official answer (this board has more than one valid layout). Place the 1–4 domino vertically on row 3, column 5 and row 4, column 5.

This board has more than one valid layout; the steps follow the official answer.